The balanced solubility equilibrium reaction of lead(II) iodide is Pbl₂(s) Pb2+ (aq) +21¯ (aq) What is the Ksp expression for lead(II) iodide? Ksp = [Pb²+][I]² ○ Ksp = [Pb²+]²[I¯] Ksp = [Pb²+][I] KSP = 2+ [Pb²+][I]² [PbI2]

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