The best predicted value of y for an adult male who is 180 cm tall is (Round to two decimal places as needed.) kg.
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- Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 142 pairs of measurements yield x=32.14cm, y=163.36cm, r=.084, P value=.32 and y=160+.111x. Find the best predicted value of y (height) given an adult female with an arm circumference of 40cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a .05 significance level.Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 136 to 190 cm and weights of 39 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yiel x= 167.51 cm, y = 81.36 kg,r= 0.232, P-value = 0.020, and y = - 103+ 1.13x. Find the best predicted value of y (weight) given an adult male who is 153 cm tall. Use a 0.01 significance level. The best predicted value of y for an adult male who is 153 cm tall is kg. (Round to two decimal places as needed.)Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 139 pairs of measurements yield x = 31.99 cm, y = 163.33 cm, r= 0.032, P-value = 0.708, and y = 158 + 0.1703x. Find the best predicted value of y (height) given an adult female with an arm circumference of 35.0 cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. %3D ..... The best predicted value is cm. (Round to two decimal places as needed.)
- Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 146pairs of measurements yield x=34.69cm, y=163.25cm, r=0.075, P-value=0.368, and y=157+0.1826x. Find the best predicted value of y (height) given an adult female with an arm circumference of 40.0cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. The best predicted value is ____cm.Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 143 pairs of measurements yield x = 32.40 cm, y = 160.39 cm, r=0.072, P-value = 0.393, and y = 157 + 0.1075x. Find the best predicted value of y (height) given an adult female with an arm circumference of 34.0 cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. %3D The best predicted value is cm. (Round to two decimal places as needed.) Enter your answer in the answer box. MacBook Pro 888 esc %24 % & 4. 9- E T. Y. H. K %#3A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed of the film and believes that this can be achieved by reducing the thickness of the film to 20 mils. Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured. For the 25-mil film, the sample data result is.x₁ = 1.15 and S₁ = 0.11, while for the 20-mil film, the data yield 2 = 1.06 and s2 = 0.09. Note that an increase in film speed would lower the value of the observation in microjoules per square inch. Do the data support the claim that reducing the film thickness increases the mean speed of the film? Use a = 0.10 and assume that the two population variances are equal and the underlying population of film speed is normally distributed. The appropriate decision for the test is to reject the null hypothesis True False
- Consider the model y=-2.45x+7.18 derived from data between x=4 and x=10. What value of x represents interpolation of the data?Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 132 to 194 cm and weights of 38 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x 167.75 cm, y=81.58 kg, r0.318, P.value = 0.001, and y-109 1.14x. Find the best predicted value of y (weight) given an adult male who is 184 cm tal, Use a 0.05 significance level. The best predicted value of y for an adult male who is 184 cm tall is kg. (Round to two decimal places as needed.)A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed of the film, and believes that this can be achieved by reducing the thickness of the film to 20 mils. Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured. For the 25-mil film, the sample data result is = 1.15 and 81 = 0.11, while for the 20-mil film, the data yield 2 = 1.06 and 82 = 0.09. Note that an increase in film speed vould lower the value of the observation in microjoules per square inch. (a) Do the data support the claim that reducing the film thickness increases the mean speed of the film? Use a = 0.10 and assume that the two population variances are equal and the underlying population of film speed is normally distributed. What is the P-value for this test? Round your answer to three decimal places (e.g. 98.765). The data the claim that reducing the film…
- A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed of the film, and believes that this can be achieved by reducing the thickness of the film to 20 mils. Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured. For the 25-mil film, the sample data result is = 1.13 and 81 = 0.11, while for the 20-mil film, the data yield = 1.08 and 82 = 0.09. Note that an increase in film speed wwould lovwer the value of the observation in microjoules per square inch. (a) Do the data support the claim that reducing the film thickness increases the mean speed of the film? Use a = 0.10 and assume that the two population variances are equal and the underlying population of film speed is normally distributed. What is the P-value for this test? Round your answer to three decimal places (e.g. 98.765). The data v the claim that reducing the…An English teacher was interested in studying the words of Macbeth. She took a random Sample of 300 words and wrote down the length of each word. She found out the average length of the words is 3.4 letters. What would be the parameter? Number of words in the sample? All words in the play? Average number of letter per words in the entire Macbeth? 3.4?A rectangular room was designed to be built for a length of 24 feet and a breadth of 15 feet. Find the Absolute Error,Relative Error and Percentage Error in the area of the room if there is a deviation in the length of the room by 1.5 feet and breadth by 1.7 feet after the construction. Absolute Error 153.3000 feet², Relative Error = 7.1758 and Percentage Error = 717.5833 %3D Absolute Error = 108.3000 feet?, Relative Error = 5.1758 and Percentage Error = 517.5833 Absolute Error = 130.8000 feet?, Relative Error = 3.1758 and Percentage Error = 317.5833 Absolute Error = 63.3000 feet?, Relative Error = 0.1758 and Percentage Error = 17.5833