The cable and spring system attached at the ring at A, is kept in equilibrium by the force F = 760N. The angle between the horisontal line and the spring AB is 0 = 30°. The angle between the vertical line and the cable AC is a = 5°. The direction of the force F is described by the ratio triangle with a = 2, b = 4.472 and c = 4. The spring constant for spring AB is k = 450N/m. Calculate the forces in the cable and the spring and complete parts (a) and (b) below.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Please help me with this question, the question asks to find force FAB and FAC. 

The cable and spring system attached at the ring at A, is kept in equilibrium by the force F = 760N.
The angle between the horisontal line and the spring AB is 0 = 30°.
The angle between the vertical line and the cable AC is a = 5°.
The direction of the force F is described by the ratio triangle with a = 2, b = 4.472 and c = 4.
The spring constant for spring AB is k = 450N/m.
Calculate the forces in the cable and the spring and complete parts (a) and (b) below.
Transcribed Image Text:The cable and spring system attached at the ring at A, is kept in equilibrium by the force F = 760N. The angle between the horisontal line and the spring AB is 0 = 30°. The angle between the vertical line and the cable AC is a = 5°. The direction of the force F is described by the ratio triangle with a = 2, b = 4.472 and c = 4. The spring constant for spring AB is k = 450N/m. Calculate the forces in the cable and the spring and complete parts (a) and (b) below.
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