The diagram below shows the trajectory for a projectile launched non-horizontally from an elevated position on top of a cliff. The initial horizontal and vertical components of the velocity are shown. Determine the horizontal and vertical components of the projectile by filling in the table shown.
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- 1つ7 3. An object undergoes motion in 2 dimensions under a constant acceleration of "-2.50 m/s at an angle of 50.0° with respect to the + x direction. It also has an initial velocity of vi = 7.00 m/s at an angle of 10,0° The object begins at the coordinates (0, 0). a) What are the coordinates of the object at t = 7.00 s? Want Cx, y) at t =?4 4tzテメ0チ=XT vse this Con Vxi = \V;l cos v +ハ Ay=lalsin Ga b) What is its total velocity vector of the object as a magnitude and direction at t = 7.00 s? a) Ov= TonA golfer strikes a golf ball on level ground.The ball leaves the ground with an initial velocity of 42 m/s [32oabove horizontal].a. Draw a vector diagram to describe the situation of the of golfball with initial velocity.b. Find the range (horizontal distance) of the golf ball travelled.c. Find the maximum height (vertical distance) the golf ballreachedA ball is thrown at an initial height of 65 feet at an initial velocity of 75 feet/second at an angle of 65 degrees. Given the parametric equations yY = - - 16t + Vo · Sin(0)t + ho and x = Vo Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 3 seconds? feet. seconds. b. When will the object hit the ground? feet. c. How far horizontally will the ball be when it hits the ground? seconds. d. When will the ball be at its maximum height? e. What is the ball's maximum height? feet. feet f. How far horizontally will the ball be when it reaches its maximum height?
- Max Height = V;*sin's (visine) 28 28 Max Ronge = v? sin 20 Vi Height 8 = 9. 81 m/sz Range 1.) A very small cannon (very small, meaning we can disregard its size) has a muzzle velocity (velocity of the projectile as it leaves the barrel) of 30 m/s and is at an angle of 35° from the ground. a.) What is the Max Height? b.) What is the Range? Somple . Diagrom Vi = inital velocty cmuzzle velocity) 0 = ongle from the grond Vi = 30 m/e Height e= 350 Ronge a) Monx Height : (30) (ain 5) Max Height = V;? sin?e 28 15- 09 m R(9.81) b.) Ronge : v.* sin 20 (30)2 sin (70*) Ronge = 86.21M * Incicode your final answers. In this case, I used a boxMOTION IN TWO DIMENSION = 30.0 m/s 20.0° (**)m A projectile is thrown from (##) = 8.1 meters above the ground. With initial velocity of 30 m/s and 20 degrees above the horizontal. Find the horizontal displacement, x. Select one: O a. 60.9562 m Ob. 91.4343 m Oc. 76.1953 m Od. 38.0976 m1110. In Fig. P-1109, a ball thrown down the incline strikes it at a distance s 254.5 It. If the ball rises to a maximum height h 64.4 ft above the point of release, compute its initial velocity vo and inclination 6. Ans. v. = 80.5 ft per see; 0= 53.1° FIG. P-1109 and P-1110.
- Mr. Brown takes a walk in the park. He first travels 600. m NW and then turns and walks 800. m @ 20.0° WoS. What is his overall displacement of his walk? Use the triangle method to solve this. Should you use the component method, I will award zero points. I know the answer, I just don’t know how to get it. Answer: 771 m @ 25.1° SoW Thanks!!3. A jet plane is flying at a constant altitude. At time it has components of velocity. At time tį = 0 it has components of velocity vz = 90", v, = 110". At time t, = 30.0 sec the components are vz = -170", v, = 40". a) Sketch the velocity vectors at t, and How do these two vectors differ? For this time interval calculate (b) the t2. components of the average acceleration, and (c) the magnitude and direction of the average acceleration.5. A ball is thrown following a projectile motion, it is known that the horizontal distance (range) the ball can travel is given by R= sin 24, where r is the range (in feet), vy is the initial speed (in ft/s), B is the angle of elevation the bal is thrown, and g=32 ft/s? is the acceleration due to gravity. a. Express the new range in terms of the original range when an angle 8 (0< @ < 45°) is doubled. b. If a balt travels a horizontai distance of 20 t when kicked at an angle of a with initial speed of 20/2 fus, find the horizontal distance it can travel when you double z. Hint: use result of item (a).
- 5. A ball is thrown following a projectile motion. It is known that the horizontal distance (range) the ball can travel is given by R = sin 20, where r is the range (in %3D feet), vo is the initial speed (in f/s), 0 is the angle of elevation the ball is thrown, and g=32 ft/s? is the acceleration due to gravity. a. Express the new range in terms of the original range when an angle 8 (0< 0 < 45°) is doubled. xiii b. If a ball travels a horizontal distance of 20 ft when kicked at an angle of a with initial speed of 20V2 ft/s, find the horizontal distance it can travel when you double a. Hint: use result of item (a).b. Prove that, the range, R the time of flight, T and the Maximum height, H by a projectile are respectively given by; vỷ sin² e R = (5/g) sin20 , T = (2v,sin®), and H = 2gH.W: An object is thrown horizontally at 20m/s from a cliff top 45m above sea level. Find (a)the time to land; (b)the angle at which it hits the water; (c)the speed at which it hits the water. Ans. (a)3.03s (b)Ø = –54. 73 (c)35.79m/s