The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage, with L₁ = 4 ft, L2= 0.5 ft, and L3 = 0.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in lb/ft³. Let g = 32.2 ft/s². Pressure gage Air Oil (p=55 lb/ft³) 4 42 Patm Mercury (p= 845 lb/ft³) g= 32.2 ft/s2

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14. thermodynamics
The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage,
with L₁ = 4 ft, L2= 0.5 ft, and L3 = 0.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in lb/ft³. Let g = 32.2
ft/s².
Pressure
gage
Air
Oil (p= 55 lb/ft³)
4
5₂2
Patm
Mercury (p = 845 lb/ft³)
g= 32.2 ft/s2
Transcribed Image Text:The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage, with L₁ = 4 ft, L2= 0.5 ft, and L3 = 0.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in lb/ft³. Let g = 32.2 ft/s². Pressure gage Air Oil (p= 55 lb/ft³) 4 5₂2 Patm Mercury (p = 845 lb/ft³) g= 32.2 ft/s2
Determine the reading of the pressure gage, in lbf/in.² (gage).
Pgage =
Oil (p=55 lb/ft³)
lbf/in.²
L₂
Patm
Mercury (p= 845 lb/ft³)
8= 32.2 ft/s2
Transcribed Image Text:Determine the reading of the pressure gage, in lbf/in.² (gage). Pgage = Oil (p=55 lb/ft³) lbf/in.² L₂ Patm Mercury (p= 845 lb/ft³) 8= 32.2 ft/s2
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