The figure shows two rings with their central axes along the x-axis. • Ring 1 has a radius R₁ = 7 cm and a charge Q₁ = 60 pC uniformly distributed over the ring. • Ring 2 has a radius R₂ = 6 cm and linear charge density A2 = -14 pC/m. . The rings are separated by a distance d = 30 cm. y [cm] Problem 3 R₁ R₂ R₁ 0 0 x [cm] Ring 2 Ring 1 The magnitude of the electric field created by ring 1 at point A can be calculated by: (9x 10)-(60-10-12)-(7-10-2) OE,= ((7-10-2)2+(7-10-2)2)¹.5 (9x109)-(60-10-12)-(7-10-2) ((7-10-2)2+(7-10-2)2)0.5 OE₁ = OE₁= E₁= ORight OLeft Oup Odown E₁ Q₂ OE₂= OE₂= OE₂= A (9x109)-(60-10-12)-(7) ((7)²+(7)2)¹.5 7. The value of the magnitude of the electric field created by ring 1 at point A is: [N/C] What is the direction of the electric field created by ring 1 at point A? The electric field created by ring 1 at point A is: +1 Ĵ[N/C] Calculate the total charge of ring 2 in Coulombs. [C] The magnitude of the electric field created by ring 2 at point A can be calculated by (9x109) (5.28x 10-12)-(0.23) ((0.23)2+(6-10-2)2)1.5 (9x 10) (5.28x 10-12)-(0.23) ((0.23)²+(6-10-2)2)0⁰.5 (9x109)-(5.28x10-12)-(0.23) ((0.23)2+(6)20.5 If the magnitude of the electric field created by ring 2 at point A is equal to E₂ = 8.13x10-13 [N/C], find the electric field vector created by the ring 2 at point A. E₂ = ]î+[ [N/C) Please answer all parts of the question.
The figure shows two rings with their central axes along the x-axis. • Ring 1 has a radius R₁ = 7 cm and a charge Q₁ = 60 pC uniformly distributed over the ring. • Ring 2 has a radius R₂ = 6 cm and linear charge density A2 = -14 pC/m. . The rings are separated by a distance d = 30 cm. y [cm] Problem 3 R₁ R₂ R₁ 0 0 x [cm] Ring 2 Ring 1 The magnitude of the electric field created by ring 1 at point A can be calculated by: (9x 10)-(60-10-12)-(7-10-2) OE,= ((7-10-2)2+(7-10-2)2)¹.5 (9x109)-(60-10-12)-(7-10-2) ((7-10-2)2+(7-10-2)2)0.5 OE₁ = OE₁= E₁= ORight OLeft Oup Odown E₁ Q₂ OE₂= OE₂= OE₂= A (9x109)-(60-10-12)-(7) ((7)²+(7)2)¹.5 7. The value of the magnitude of the electric field created by ring 1 at point A is: [N/C] What is the direction of the electric field created by ring 1 at point A? The electric field created by ring 1 at point A is: +1 Ĵ[N/C] Calculate the total charge of ring 2 in Coulombs. [C] The magnitude of the electric field created by ring 2 at point A can be calculated by (9x109) (5.28x 10-12)-(0.23) ((0.23)2+(6-10-2)2)1.5 (9x 10) (5.28x 10-12)-(0.23) ((0.23)²+(6-10-2)2)0⁰.5 (9x109)-(5.28x10-12)-(0.23) ((0.23)2+(6)20.5 If the magnitude of the electric field created by ring 2 at point A is equal to E₂ = 8.13x10-13 [N/C], find the electric field vector created by the ring 2 at point A. E₂ = ]î+[ [N/C) Please answer all parts of the question.
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![The figure shows two rings with their central axes along the x-axis.
• Ring 1 has a radius R₁ = 7 cm and a charge Q₁ = 60 pC uniformly distributed over the ring.
• Ring 2 has a radius R₂ = 6 cm and linear charge density A2 = -14 pC/m.
•The rings are separated by a distance d = 30 cm.
Problem 3.
-- R₁
R₁
0
Ring 1
1
OE₁=
5
OE,=
2.
4.
E₁
The magnitude of the electric field created by ring 1 at point A can be calculated by:
(9x 10°) (60-10-12)-(7-10-2)
((7-10-2)²+(7-10-2)2)1.5
OE₁ =
6
E₁ =
Q₂ =
ORight
OLeft
Oup
Odown
OE₂=
y [cm]
OE₂=
OE₂ =
-
7.
A
(9x109) (60-10-12)-(7-10-2)
((7-10-2)2+(7-10-2)2)0.5
(9x109) (60-10-12) (7)
((7)²+(7)²)1.5
R₂
Ring 2
x [cm]
The value of the magnitude of the electric field created by ring 1 at point A is:
[N/C]
What is the direction of the electric field created by ring 1 at point A?
The electric field created by ring 1 at point A is:
i +[
[N/C]
Calculate the total charge of ring 2 in Coulombs.
[C]
The magnitude of the electric field created by ring 2 at point A can be calculated by:
(9x109) (5.28x10-12)-(0.23)
((0.23)2+(6-10-2)2)1.5
(9x 10°) (5.28x10-12)-(0.23)
((0.23)²+(6-10-2)2) 0.5
(9x109)-(5.28x10-12) (0.23)
((0.23)²+(6)²)0.5
If the magnitude of the electric field created by ring 2 at point A is equal to E₂ =
8.13x10-13 [N/C], find the electric field vector created by the ring 2 at point A.
E₂ =
]+[
Ĵ[N/C]
Please answer all parts of the question.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F621c65f8-44f1-4cab-98a0-cd79230825b8%2F8f0cd88c-8bc7-4d7b-9078-3a4ace56b3f3%2Fdjxsnyd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The figure shows two rings with their central axes along the x-axis.
• Ring 1 has a radius R₁ = 7 cm and a charge Q₁ = 60 pC uniformly distributed over the ring.
• Ring 2 has a radius R₂ = 6 cm and linear charge density A2 = -14 pC/m.
•The rings are separated by a distance d = 30 cm.
Problem 3.
-- R₁
R₁
0
Ring 1
1
OE₁=
5
OE,=
2.
4.
E₁
The magnitude of the electric field created by ring 1 at point A can be calculated by:
(9x 10°) (60-10-12)-(7-10-2)
((7-10-2)²+(7-10-2)2)1.5
OE₁ =
6
E₁ =
Q₂ =
ORight
OLeft
Oup
Odown
OE₂=
y [cm]
OE₂=
OE₂ =
-
7.
A
(9x109) (60-10-12)-(7-10-2)
((7-10-2)2+(7-10-2)2)0.5
(9x109) (60-10-12) (7)
((7)²+(7)²)1.5
R₂
Ring 2
x [cm]
The value of the magnitude of the electric field created by ring 1 at point A is:
[N/C]
What is the direction of the electric field created by ring 1 at point A?
The electric field created by ring 1 at point A is:
i +[
[N/C]
Calculate the total charge of ring 2 in Coulombs.
[C]
The magnitude of the electric field created by ring 2 at point A can be calculated by:
(9x109) (5.28x10-12)-(0.23)
((0.23)2+(6-10-2)2)1.5
(9x 10°) (5.28x10-12)-(0.23)
((0.23)²+(6-10-2)2) 0.5
(9x109)-(5.28x10-12) (0.23)
((0.23)²+(6)²)0.5
If the magnitude of the electric field created by ring 2 at point A is equal to E₂ =
8.13x10-13 [N/C], find the electric field vector created by the ring 2 at point A.
E₂ =
]+[
Ĵ[N/C]
Please answer all parts of the question.
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