The first cycle will have stops and the second cycle will have stops.
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A: Cycle time is the total time spent to manufacture a single unit of item.
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A: Given data; Output = 60 units Available time = 8 hrs or 8*60 = 480 min
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A: The task flow diagram for the product is given below.
Q: A manufacturer is designing a product layout for a new product production. It plans to use a…
A: Demand = 100 units Time available = 8×60= 480 minutes
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A: LPT rule: Sequence Job 1 E 2 D 3 C 4 A 5 B
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A: Cycle time = Total Available time Desired Output
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A: FCFS: The sequence will be as per the arrival i.e. A, B, C, D, E.
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- The mean service time (x¯) of a hairdresser is 18 minutes with a standard deviation (σ) of 2 minutes. Upper specification limit (USL) is 22 minutes, whereas lower specification limit (LSL) is 15 minutes for this process. What is the process capability index (cpk) for this process? Is the process capable? Cpk=0.67, capable Cpk=1.5, capable Cpk=0.67, not capable Cpk=0.5, capable Cpk=0.5, not capableThe mean service time (x¯) of a physician is 25 minutes with a standard deviation (σ) of 1 minute. Upper specification limit (USL) is 30 minutes, whereas lower specification limit (LSL) is 20 for this process. What is the process capability ratio (cp) for this process? Is the process capable? Cp=1, barely capable Cp=1.5, capable Cp=1, not capable Cp=1.67, not capable Cp=1.67, definitely capablei need help with calculating rate of diffusion for 3 crystals and 6 crystals Diffusion Diffusion Diffusion Spot Spot Time Spot Diameter 1 Diameter 3 Diameter 6 (min) Crystal Crystals Crystals (mm) (mm) (mm) 10 15 0-15 0-15 20 16 0-16 0-16 30 18 0-18 0-18 Time Rate of Diffusion for Rate of Diffusion for 3 Crystals Rate of Diffusion for 6 Crystals (min) 1 Crystal (mm/hr) 0-10 90 0-20 48 0-30 36 (mm/hr) (mm/hr) Rate [mm/h] = (diameter [mm] / time [min]) x 60 [min] X
- A manager is simulating the number of times a machine operator stops a machine to make adjustments. After careful study the manager found that the number of stops ranged from one to five per cycle and that each number of stops was equally likely. Using the random numbers 0.77 and 0.62 (in that order), determine how many stops for adjustments each of the next two cycles will have. The first cycle will have stops and the second cycle will have stops.When a computer system verifies a user by voice recognition, it is using a: Question 36 options: biometric control hardening intrusion detection corrective controlA primary method of observation using the internet is to count the number of times a Web page is visited. * O True False
- There is a 4 percent error rate at a specific point in a production process. If an inspector is placed at this point, all the defects can be detected and eliminated. The inspector would cost $9 per hour and could inspect units in the process at the current production rate of 46 per hour. If no inspector is hired and defects are allowed to pass this point, there is a cost of $10 per defective unit to correct the defects later on. Assume that the line will operate at the same rate (i.e., the current production rate) regardless of whether the inspector is hired or not. a. if the inspector is hired, what will be the inspection cost per unit? b. if an inspector is not hired, what will be the defective cost per unit? c. should an inspector be hired based on costs alone?Output from a process contains 0.02 defective unit. Defective units that go undetected into final assemblies cost $25 each to replace. An inspection process, which would detect and remove all defectives, can be established to test these units. However, the inspector, who can test 20 units per hour, is paid $8 per hour, including fringe benefits. Should an inspection station be established to test all units? Assume that the line will operate at the same rate (i.e., the current production rate) regardless of whether or not the inspection operation is added. a-1. Without the inspector, what is the current hourly cost of defects? a-2. Should an inspection station be established to test all units based on costs alone? multiple choice Yes No a-3. If the inspection operation is added, what would be the cost to inspect each unit? Note: Round your answer to 2 decimal places. b. What would be the benefit (or loss) from establishing the inspection process? Note: Round your answer…Yelp Dog Food produces specialized dog foods in 1-pound packages. The amount of dog food in each package should be 1 pound, and Yelp has determined that the standard deviation of the machine filling these packages is half an ounce, and the confidence interval is 14.85% (z = .1872). In order to confirm that the machine is operating properly, Yelp takes 16 sample bags every hour and weighs them. The means of these 16 bags for an 8-hr shift is given below. 1 2 3 4 5 6 7 8 0.98 1.01 0.97 1.03 1.01 0.94 1.02 1.02 NARREND What would be the lower control limit? .9038 .9567 .9741 .9892
- Yelp Dog Food produces specialized dog foods in 1-pound packages. The amount of dog food in each package should be 1 pound, and Yelp has determined that the standard deviation of the machine filling these packages is half an ounce, and the confidence interval is 14.85% (z = .1872). In order to confirm that the machine is operating properly, Yelp takes 16 sample bags every hour and weighs them. The means of these 16 bags for an 8-hr shift is given below. 1 2 3 4 5 6 7 8 0.98 1.01 0.97 1.03 1.01 0.94 1.02 1.02 NARREND How many, if any, of the hours were out of control? 0 2 3 7Yelp Dog Food produces specialized dog foods in 1-pound packages. The amount of dog food in each package should be 1 pound, and Yelp has determined that the standard deviation of the machine filling these packages is half an ounce, and the confidence interval is 14.85% (2= 1872). In order to confirm that the machine is operating properly, Yelp takes 16 sample bags every hour and weighs them. The means of these 16 bags for an 8-hr shift is given below. 1. 2. 3. 4 5. 6. 8 0.98 1.01 0.97 1.03 1.01 0.94 1.02 1.02 13. For this one day's worth of filling bags, what would be the upper control limit? A. 1.0000 B. 1.0209 C. 1.0324 D. 1.0913 14. What would be the lower control limit? A. .9038 B. 9567 C.9741 D..9892 15. How many, if any, of the hours were out of control? A.O B. 2 C.3 D. 7While analyzing their annual sales data (liters of wine sold per year) for the past 30 years, a vineyard found that after taking four successive differences, the resulting data had a mean of 2458 liters and looked like a stationary process (e.g. white noise). If the actual data for the past four years were 2018 - 2134 liters, 2017 - 2403 liters, 2016 - 2076 liters, and 2015 - 2290 liters. What would be a reasonable forecast for sales in 2019? Explain.