The free energy change for the following reaction at 25 °C, when [Hg2+] = 1.19 M and [Zn²+] = 3.01x10-³ M, is -327 kJ: Hg2+(1.19 M) + Zn(s)→→→ Hg(1) + Zn²+(3.01×10-³ M) AG = -327 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
The free energy change for the following reaction at 25 °C, when [Hg2+] = 1.19 M and [Zn²+] = 3.01x10-³ M, is -327 kJ: Hg2+(1.19 M) + Zn(s)→→→ Hg(1) + Zn²+(3.01×10-³ M) AG = -327 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
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Chapter18: Thermodynamics And Equilibrium
Section: Chapter Questions
Problem 18.79QP: Is the following reaction spontaneous as written? Explain. Do whatever calculation is needed to...
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The free energy change for the following reaction at 25 °C, when [Hg2+] = 1.19 M and [Zn²+] =
3.01x10-3 M, is -327 kJ:
Hg2+(1.19 M) + Zn(s)→→→→→ Hg(1) + Zn²+(3.01×10-³ M) AG = -327 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe97ce114-f41d-4f30-8ae1-73636b0d3142%2Fa1dbef64-cc14-4595-95aa-505978c3bd24%2F6hhhiyp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:=
The free energy change for the following reaction at 25 °C, when [Hg2+] = 1.19 M and [Zn²+] =
3.01x10-3 M, is -327 kJ:
Hg2+(1.19 M) + Zn(s)→→→→→ Hg(1) + Zn²+(3.01×10-³ M) AG = -327 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?
![The free energy change for the following reaction at 25 °C, when [Zn²+] = 1.74×10-³ M and
[Cr³+] = 1.15 M, is 29.4 kJ:
3Zn²+(1.74x10-³ M) + 2Cr(s)→→→3Zn(s) + 2Cr³+(1.15 M) AG 29.4 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe97ce114-f41d-4f30-8ae1-73636b0d3142%2Fa1dbef64-cc14-4595-95aa-505978c3bd24%2Fveiab7b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Zn²+] = 1.74×10-³ M and
[Cr³+] = 1.15 M, is 29.4 kJ:
3Zn²+(1.74x10-³ M) + 2Cr(s)→→→3Zn(s) + 2Cr³+(1.15 M) AG 29.4 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?
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