The fur color gene in rabbits has a dominant allele B with a black phenotype and a recessive allele with a brown phenotype. The rabbit hair length gene has a dominant allele S for short hair, and a long hair recessive allele s. In a cross between a homozygous black-long-hair rabbit with a homozygous brown-short rabbit, what would be the genotype(s) B_S_ and phenotype(s) [ Select ] of the F1 generation? What would be the genotype(s) [ Select ] and phenotype(s) [ Select ] v of the F2 generation?
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- In mice, the A allele causes agouti fur, the AY allele causes yellow fur and is dominant to the A allele. The homozygous AY AY genotype is lethal. Why is the AYAY homozygous condition lethal?The white Leghorn breed of chickens is homozygous for the dominant allele C, which produces colored feathers. However, this breed is also homozygous for the dominant allele I of an independently assorting gene that inhibits coloration of the feathers. Consequently, Leghorn chickens have white feathers. The white Wyandotte breed of chickens has neither the allele for color nor the inhibitor of color; it is therefore genotypically cc ii. What are the F2 phenotypes and proportions expected from intercrossing the progeny of a white Leghorn hen and a white Wyandotte rooster?In mice, the A allele causes agouti fur, the AY allele causes yellow fur and is dominant to the A allele. The homozygous AY AY genotype is lethal. Why is the AYAY homozygous condition lethal? The AY allele highly transcribes the merc gene which is lethal in a homozygous AYAY individual. None of the other answers are correct. The AY allele lacks an upstream merc gene which is required for normal embryonic development. The AY allele contains a null mutation in the A gene, which is required for normal embryonic development. The yellow pigment produced by A allele is required for survival.
- In mice, an allele for apricot eyes (a) is recessive to an allele for brown eyes (a+). At an independently assorting locus, an allele for tan coat color (t) is recessive to an allele for black coat color (t+). A mouse that is homozygous for brown eyes and black coat color is crossed with a mouse having apricot eyes and a tan coat. The resulting F1 are intercrossed to produce the F2. In a litter of eight F2 mice, what is the probability that two will have apricot eyes and tan coats?In bears fur colour can be either yellow or tan, and is determined by two alleles of the C gene. A heterozygous bear is observed to present a fur pattern of yellow and tan patches. Explain why this can occur.A recessive maternal effect mutant in zebrafish, called ichabod, results in embryos lacking heads that are non-viable. You have been instructed to identify females that are homozygous for the ichabod mutant allele. At your disposal are a tank of wild-type fish (males and females), a tank of male and female parental fish that are all heterozygous for the ichabod mutant allele (ichabod/+), and a tank of F1 fish derived from a cross between a heterozygous male and heterozygous female (ichabod/+). Which of the following would be a way to identify females that are homozygous mutant, i.e. ichabod/ichabod? Select all answers that would work.
- Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口Bronze coloured turkey is controlled by a dominant allele, B. Red coloured turkey is homozygous for a recessive allele bb. Dominant gene N produce normal feather and recessive genotype produce ‘hairy’ feather nn. In a cross between homozygous bronzed coloured turkey with ‘hairy’ feather and homozygous red coloured turkey with normal feather. What are the ratios of F2 progeny with Bbnn genotypes? (I want to check if what i'm doing is correct)In chickens, the black (B) and white (W) alleles for feather color are codominant. If a homozygous white chicken is crossed with a homozygous black chicken, the offspring has feathers that are both black and white, a trait that is known as erminette, as shown in the diagram. + The Punnett square shows the possible genotypes resulting from the cross with a white chicken. f an erminette chicken White Chicken W W B BW BW W ww Select the correct answers from the dropdown menus to complete the sentence to indicate the. expected percentage of offspring with each phenotype resulting from the cross shown in the Punnett square. The expected phenotype percentages of offspring are [ Select ] % black, (Select] % white, [ Select ] % erminette. Erminette Chicken
- In rabbits, white coat color (CW) and black coat color (CB) are codominant, and both of these alleles are dominant over albino (c); heterozygotes (CWCB) are spotted. Consider a cross between a heterozygous black-coated rabbit and a homozygous white-coated rabbit.In the snail Cepaea nemoralis, an autosomal allele causing a banded shell, u, is recessive to the allele for an unbanded shell, U. Genes at a different locus determine the background color of the shell. The allele for a yellow shell, b, is recessive to the allele for a brown shell, B. A banded, yellow snail is crossed with a homozygous brown, unbanded snail. The F1 progeny are then crossed with banded, yellow snails in a testcross. Predict the percentage of progeny in each phenotype if the two genes are linked with no recombination, if the two genes assort independently, and if the genes are 20 m.u. apart. Place the percentage for each phenotype for each of the scenarios in the table. Percentages can be used more than once. Phenotype Brown, unbanded Brown, banded Yellow, unbanded Yellow, banded 80% 50% 100% Linked, Independent no recombination assortment 25% 10% Answer Bank 75% 90% 60% 70% 20% Genes 20 m.u. apart 40% 30% 0%In rabbits, white coat color (CW) and black coat color (CB) are codominant, and both of these alleles are dominant over albino (c); heterozygotes (CWCB) are spotted. Predict the genotypes and phenotypes of the offspring from a heterozygous black-coated rabbit and a homozygous white-coated rabbit.