The 'H-NMR of the product shows signals (two doublets) in the aromatic region and a very broad signal (the signal is almost flat from -5.0 ppm to -6.5 ppm and may actually extend into the H doublet at ~ 6.7 ppm) which may indicate a "combination" of the amine and acid peaks. (The small peak at 2 ppm should be ignored.) H d b

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter24: Carboxylic Acids & Derivatives
Section: Chapter Questions
Problem 3E
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1. The ¹H-NMR of the product shows signals (two doublets) in the
aromatic region and a very broad signal (the signal is almost flat
from ~5.0 ppm to -6.5 ppm and may actually extend into the H
doublet at ~ 6.7 ppm) which may indicate a "combination" of the
amine and acid peaks. (The small peak at ~ 2 ppm should be
ignored.)
H
"HA
H
d
a
b
C
Transcribed Image Text:1. The ¹H-NMR of the product shows signals (two doublets) in the aromatic region and a very broad signal (the signal is almost flat from ~5.0 ppm to -6.5 ppm and may actually extend into the H doublet at ~ 6.7 ppm) which may indicate a "combination" of the amine and acid peaks. (The small peak at ~ 2 ppm should be ignored.) H "HA H d a b C
a.
b.
C.
The amine group can be considered to be electron donating toward the ring by resonance, thus it
will place a partial negative charge on the (relative) ortho and para positions. Draw three
resonance structures for the product, showing the resulting charges at these positions. Will this
resonance effect lead to shielding or deshielding for the protons labelled as Hb compared to Hc?
Based on your answer, which of the protons (Hb or Hc) should be at larger chemical shift (lower
field)? Explain briefly.
The carboxylic acid is considered to be electron withdrawing by resonance, thus it will place a
partial positive charge on the (relative) ortho and para positions. Draw three resonance
structures for the product, showing the resulting charges at these positions. Will this resonance
effect lead to shielding or deshielding for the protons labelled as Hc compared to Hb? Based on
your answer, which of the protons (Hb or Hc) should be at larger chemical shift (lower field)?
Explain briefly.
After the previous two parts of this question have been completed, fill in the table on the
previous page. Note that you should be able to predict how the spectrum should appear, but
you will not see the expected peaks for some of the signals. If the spectrum does not clearly
show the some of the signals, you write "inconclusive" in the table cells for those observations.
Transcribed Image Text:a. b. C. The amine group can be considered to be electron donating toward the ring by resonance, thus it will place a partial negative charge on the (relative) ortho and para positions. Draw three resonance structures for the product, showing the resulting charges at these positions. Will this resonance effect lead to shielding or deshielding for the protons labelled as Hb compared to Hc? Based on your answer, which of the protons (Hb or Hc) should be at larger chemical shift (lower field)? Explain briefly. The carboxylic acid is considered to be electron withdrawing by resonance, thus it will place a partial positive charge on the (relative) ortho and para positions. Draw three resonance structures for the product, showing the resulting charges at these positions. Will this resonance effect lead to shielding or deshielding for the protons labelled as Hc compared to Hb? Based on your answer, which of the protons (Hb or Hc) should be at larger chemical shift (lower field)? Explain briefly. After the previous two parts of this question have been completed, fill in the table on the previous page. Note that you should be able to predict how the spectrum should appear, but you will not see the expected peaks for some of the signals. If the spectrum does not clearly show the some of the signals, you write "inconclusive" in the table cells for those observations.
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