The necessary value for z Sample 1 Sample 2 n₁ = 400 n₂ = 300 P1 = 0.56 P₂ = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. lower bound = P₁ P2-²a/2V P₂(1-P₂) 7₂ upper bound was determined to be 1.645. Recall the given information. a/2 = 0.56 0.41 0.0559 = = 0.56 0.41 02441 P₁(1-P₁) n1 + Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₂(1-P₂) P₁-P₂ + ²a/2√ P₁(1-P₁) + n₁ 7₂ X 1.645, 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 + 0.56(10.56) 0.41(10.41) 400 300 +
The necessary value for z Sample 1 Sample 2 n₁ = 400 n₂ = 300 P1 = 0.56 P₂ = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. lower bound = P₁ P2-²a/2V P₂(1-P₂) 7₂ upper bound was determined to be 1.645. Recall the given information. a/2 = 0.56 0.41 0.0559 = = 0.56 0.41 02441 P₁(1-P₁) n1 + Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₂(1-P₂) P₁-P₂ + ²a/2√ P₁(1-P₁) + n₁ 7₂ X 1.645, 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 + 0.56(10.56) 0.41(10.41) 400 300 +
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
Related questions
Question
100%
Transcribed Image Text:upper bound = P₁ P₂
+Z
= 0.56 0.41
02441
a/2
P₁(1-P₁) P₂(1-P₂)
01
7₂
+
Submit Skin (you cannot como bal
+1.645,
0.56(1-0.56)
400
+
Ing the result to four decimal places.
X
Therefore, a 90% confidence interval for the difference in the population proportions (rounding to four decimal places) is from a lower
bound of 0.0559
X to an upper bound of 0.2441
0.41(10.41)
300
Transcribed Image Text:Step 3
The necessary value for Za/2 was determined to be 1.645. Recall the given information.
Sample 1
n1 = 400
P1 = 0.56
P2 = 0.41
Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places.
P₁(1-P₁) P₂(1-P₂)
1
72
lower bound =
P₁-P₂-²a/2
= 0.560.41
Sample 2
n2 = 300
= 0.0559
=
0.56 0.41
= 02441
X
Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places.
P₁(1-P₁) P₂(1-P₂)
upper bound = P₁ P₂ + ²a/2√
n1
n2
X
+
✔
- 1.645,
+
0.56(1 0.56) 0.41(10.41)
300
+1.645.
400
0.56(1 0.56)
+
400
+
0.41(1 0.41)
300
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