The particle size distribution curves for three soils - A, B and C - are shown in Figure Q-2 on page 2. a. Determine the effective size, average particle size, uniformity coefficient and coefficient of curvature for soil B. b. Classify soil A according to ASTM-CS. C. Classify soil C according to the AASHTO system. The Atterberg limits for this soil are LL = 81 and PL = 35. Using sketches and notes, outline the key features of the SPT test.

The particle size distribution curves for three soils - A, B and C - are shown in Figure Q-2 on page 2. a. Determine the effective size, average particle size, uniformity coefficient and coefficient of curvature for soil B. b. Classify soil A according to ASTM-CS. C. Classify soil C according to the AASHTO system. The Atterberg limits for this soil are LL = 81 and PL = 35. Using sketches and notes, outline the key features of the SPT test.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.1CTP: Since laboratory or field experiments are generally expensive and time consuming, geotechnical...

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Given the following Sieve Analysis and Atterberg limits results. Answer the following questions: 1- What is the effective diameter of this soil? 2- Calculate the uniformity coefficient and coefficient of gradation 3- Determine the percentage of Gravel, Sand, Fine soils according to USCS. 4- Classify the soil using AASHTO (with GI) & USCS (with group name). Diameter Sieve # % Passing 100 (тm) 90 4 4.75 96 80 3.35 90 70 10 78.8 60 20 0.85 56.8 50 40 0.425 37.8 40 60 0.25 23.6 30 100 0.15 13 20 200 0.075 4.6 10 Рan LL 10 10 0.1 0.01 Diameter PL 5 Percent Passing (%) 2.
Since laboratory or field experiments are generally expensive and time consuming, geotechnical engineers often have to rely on empirical relationships to predict design parameters. Section 6.6 presents such relationships for predicting optimum moisture content and maximum dry unit weight. Let us use some of these equations and compare our results with known experimental data. The following table presents the results from laboratory compaction tests conducted on a wide range of fine-grained soils using various compactive efforts (E). Based on the soil data given in the table, determine the optimum moisture content and maximum dry unit weight using the empirical relationships presented in Section 6.6. a. Use the Osman et al. (2008) method [Eqs. (6.15) through (6.18)]. b. Use the Gurtug and Sridharan (2004) method [Eqs. (6.13) and (6.14)]. c. Use the Matteo et al. (2009) method [Eqs. (6.19) and (6.20)]. d. Plot the calculated wopt against the experimental wopt, and the calculated d(max) with the experimental d(max). Draw a 45 line of equality on each plot. e. Comment on the predictive capabilities of various methods. What can you say about the inherent nature of empirical models?
Subject: Soil Mechanics A. Classify the Soil Using USCS (with explanation/ justification) Given data: D10 = ? D30= 0.0023mm D60= 0.032mm Liquid Limit= 49% Plastic Limit= 24% CHOICES: a. CL (lean clay with gravel) b. CL ( lean clay with sand) c. ML (silt with gravel) d. ML (Silt with sand)
Q1: Use the USCS to Classify the soil sample with the following data: % passing 4.75 mm Sieve = 64 % passing 75- Sieve =4 Uniformity Coefficient= 7.5 Coefficient of Curvature=2.7 Plasticity index = 2.5 Solution: Q2: Use the USCS to Classify the soil samples with the following data dalla Soil LL PL Group Symbol Soil Name 15 35 25 ABC 8. ८८ 25 45 65 2-Seepage velocity (m/s) = 70 3- Flow rate in (m3/s) = oss and dry ng www Parmbly & volume change decrease Campering wes Toughness and dry strength dease Presby & val change in 10 20 30 40 50- 60 Liepakt. 70 80 Atra -0.73 (W₂-201 90 Q3: For the soil shown below the hydraulic conductivity is (3 m/day). The sample diameter is 1.5 m. The porosity is (30%). Find: 1- Flow velocity (m/s)== 100 110 120 Soil 4 m ITE
C 1. Sieve analysis data for two inorganic soils are provided in Table 1. Soil 1 has LL = 60 and PL = 36. Soil 2 has LL = 23 and PL =15. To plot the particle size distribution curves for Soils 1 and 2 using the attached sheet. Determine the effective grain size, D10 for Soil 2. Determine the USCS designation for each soil. List step by step how you make your choices. Table 1. Sieve Analysis Data. Mesh Sieve No. 4 10 20 40 60 100 200 opening (mm) 4.750 2.000 0.850 0.425 0.250 0.150 0.075 Soil 1 % finer 100 100 98 93 88 83 77 Soil 2 % finer 100 90 64 38 29 21 11 % Finer 120 100 80 60 40 20 II 1 11 10 T+4- I I J FT T I 1 Bullie aller 1 1 1 TEE J 1 I 01: 1 H I I F + +4 F T LLU 1 L 1 1 4 II FT 7 LI 1 TT IT 1 1 31 11 1 LI J-L IT J { LIL II 1 1 rt II I T LI L 11 J J FIL I 31 I I 1 I B 1 1 T r T 1 CA J <-+ I 1 Particle Size Distribution 1 I THE SE DET L II LL t FT4 JII 1 1 1 1 Fr-r 7 1 J Lead L 1 I T I P E S I - 1 1 I E T I Particle size (mm) II LL 1 T E T TH 0.1 J J E IF LIL II F 1 1 T J II T…
The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
Classify the given soils using the Unified Soil Classification System (USCS). Give the group symbols and group names. (Show the path of the classification.) Sieve Analysis (percent finer) Soil No. No. 4 No. 200 LL PL Comments A 94 3 NP Cy = 4.48 and C = 1.22 - В 100 77 63 25 B.
How field identification of clayey soil can be done from silty soil using simpler field tests. Find the group index value according AASTHO soil classification system by using following data. % passing 75 micron sieve = 58%, Liquid limit = 50% Plastic Limit = 35 %
12. Situation 12 - The given data shows the sieve analysis of three soil samples. a. Compute for the group index of Soil B. b Compute for the group index of Soil A. c. Compute for the group index of Soil C
The size characteristics of the soil particles are shown in the table below. Classify soil using: 1. USDA Method 2. AASHTO Method (Including group index) 3. USCS Method (Full Soil Name not Symbol only) Size (mm) Percent finer 4.7500 93 2.0000 77 0.0330 69 0.0180 55 0.0100 42 0.0062 33 0.0018 24 0.0010 12 From consistency limit test, the following results are determined: Liquid Limit 32% Plastic Limit 24%
Problem 2 Classify the soil using USCS system. Give the group symbols and group names. Soil Sieve Analysis- LL PL Cu Ce Percent Finer # 4 # 200 70 30 33 12 b 48 20 41 19 95 70 52 24 100 82 30 11 e 71 11 32 16 4.8 2.9 f 90 8. 39 8. 3.9 2.1 Problem 3 Classify the soil based on USDA textural classification Particle Size Distribution (%) Soil Sand Clay 40 20 Silt 55 C 45 35
Given the data of sieve analysis of the soil; 1. Determine the approximate effective size of the soil (choices: 0.115mm, 0.140mm, 0.093mm, 0.079mm) 2. Determine the approximate coefficient of curvature (choices: 0.84, 1.03, 0.51, 0.69) 3. Classify the soil using the AASHTO classification system