The sodium iodide test is used to identify primary alkyl halides and it also takes place via a substitution reaction. Describe the test including the reactions that explain the full mechanism. Explain whether this reaction follows a SN1 or a SN2 mechanism.
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The sodium iodide test is used to identify primary
Describe the test including the reactions that explain the full mechanism. Explain whether this reaction follows a
SN1 or a SN2 mechanism.
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- Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions -X티 Hö: H-O -CH3 -CH3 H30*Give the products of the following substitution reactions. For every reaction, show electron pairs on both nucleophile and leaving group.
- Fill the blank space. Compounds containing a phenol group may work as ANTIOXIDANTS to prevent free radical damage. This is accomplished when a free radical (or UV light) encounters a phenol group, turning the phenol group into a radical. However, contrary to typical radical behavior, the structure of the phenol radical can neutralize (or quench) the unpaired electron. Specifically, the phenol structure neutralizes (or quenches) the unpaired radical electron by doing the following: taking the electron and ---------. The correct name (or abbreviation) of an example compound containing a phenol group with antioxidant properties is: ---------.This reaction does not follow the expected theory. Given what you know about substitution/elimination, what is the expected mechanism this reaction should follow? Suggest why that is not what happens and give the actual product of the reaction. Br ткон sAlkyl halides undergo nucleophilic substitution and elimination reactions. When the kinetics of the reaction are measured, if the rate of the reaction is found to be dependent only upon the concentration of the alkyl halide the reaction is first order. The substitution reaction is thus termed SN1, and the elimination reaction is termed E1. These reactions are unimolecular and occur in two steps. The first step is rate-limiting and involves the loss of the leaving group to form a carbocation. In the second, fast, step the nucleophile adds to the carbocation in the SN1 reaction or elimination occurs to give an alkene in the E1 reaction. Because the carbocation is planar, the nucleophile can add to either face and therefore racemization is usually observed although solvent effects can influence this somewhat. E1 elimination follows Zaitsev’s rule and typically yields the most substituted alkene as the major product. Conditions which favor the SN1/E1 pathway include the use of a weak…
- Alkyl halides undergo nucleophilic substitution and elimination reactions. When the kinetics of the reaction are measured, if the rate of the reaction is found to be dependent only upon the concentration of the alkyl halide the reaction is first order. The substitution reaction is thus termed SN1, and the elimination reaction is termed E1. These reactions are unimolecular and occur in two steps. The first step is rate-limiting and involves the loss of the leaving group to form a carbocation. In the second, fast, step the nucleophile adds to the carbocation in the SN1 reaction or elimination occurs to give an alkene in the E1 reaction. Because the carbocation is planar, the nucleophile can add to either face and therefore racemization is usually observed although solvent effects can influence this somewhat. E1 elimination follows Zaitsev’s rule and typically yields the most substituted alkene as the major product. Conditions which favor the SN1/E1 pathway include the use of a weak…Please answer the two items. The following compounds are major products of an elimination reaction with an alkyl halide. Determine the structure of the alkyl halide. Write the overall reaction mechanism. Tip: Remember your Markovnikov’s rule. Follow the progress of the reaction and look at the stability of the intermediate products and transition states to determine the minor and major products.Write the mechanism leading to the product(s) for the acid-base reactions below. Label the acid, base, nucleophile, and electrophile. Where possible, label the conjugate base and the conjugate acid.
- Convert 2-pentanol into 2,3-dibromopentane. Draw structures of the starting material (2-pentanol) and final product (2,3-dibromopentane), and show the two reactions needed for this synthesis. Include the structure of the intermediate compound, and the reagents and conditions for each reaction. Then explain why 1,2-dibromopentane would not be a significant product of this synthesis.In the second paragraph you should explain why 2-chloro-2-methylpropane reacts with water via the SN1 mechanism instead of the SN2 mechanism, and then write the steps in the mechanism for this reaction. Then write the balanced equation for the reaction between 2-methyl-2-chloropropane and water. One of the products of this reaction is HCl. The rate at which HCl is produced is equal to the rate at which 2-chloro-2-methylpropane is consumed. In this experiment, the HCI will be neutralized by incremental addition of a sodium hydroxide solution. Write the balanced equation for the reaction between NaOH and HCI.Choose the best reagents from the list provided below for carrying out the following conversion. Match the reagent with the step number. HCl (aq), Zn(Hg) KMnO4, H3O+ CH3Cl, AlCl3 HNO3, H2SO4 Cl2, FeCl3 fuming sulfuric acid