Theorem: Quotient RuleIf f(x)=T(x)B(x)is the quotient of differentiable functions, thenB'(x)T'(x) T'(x)B'(x)-f'(x) =[B'(x)]2T'(x)f'(x) =B'(x)f'(x)=B(x)T'(x) + T(x)B′(x)[B(x)]2-B(x)T'(x) T(x)B'(x)f'(x) ==[B(x)]²B(x)T'(x) – T(x)B′(x)-f'(x) =[B'(x)]²B'(x)T(x) T'(x)B(x)f'(x) =[B(x)]²

Answered: Image /qna-images/answer/d3a9ffcc-99fe-4957-a5e7-14b8df9fb486.jpg

Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then. f'(x) = B'(x)T'(x) – T'(x)B′(x) - [B'(x)]2 T'(x) f'(x) = B'(x) f'(x) = f'(x) = B(x)T'(x)+T(x)B′(x) [B(x)]2 - B(x)T'(x) T(x)B'(x) [B(x)]2 B(x)T'(x) – T(x)B′(x) - f'(x) = [B'(x)]² B'(x)T(x) T'(x)B(x) f'(x) = [B(x)]2

Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then. f'(x) = B'(x)T'(x) – T'(x)B′(x) - [B'(x)]2 T'(x) f'(x) = B'(x) f'(x) = f'(x) = B(x)T'(x)+T(x)B′(x) [B(x)]2 - B(x)T'(x) T(x)B'(x) [B(x)]2 B(x)T'(x) – T(x)B′(x) - f'(x) = [B'(x)]² B'(x)T(x) T'(x)B(x) f'(x) = [B(x)]2

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter9: Multivariable Calculus

Section9.CR: Chapter 9 Review

Problem 54CR

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