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This gives us TA 1 8 cos(0) + 16 cos( os() +16 cos COS(1) +16 cos 4 COS(1/6) + 8 cos(1) 5(1)] = 8 = (rounded to six decimal places) Therefore, using the Trapezoidal Rule with n = 4 and rounding to six decimal places we have 1 √² 8 cos(x²) dx =

This gives us TA 1 8 cos(0) + 16 cos( os() +16 cos COS(1) +16 cos 4 COS(1/6) + 8 cos(1) 5(1)] = 8 = (rounded to six decimal places) Therefore, using the Trapezoidal Rule with n = 4 and rounding to six decimal places we have 1 √² 8 cos(x²) dx =

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.4: Multiple-angle Formulas
Problem 72E
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This gives us TA 1 8 cos(0) + 16 cos( os() +16 cos COS(1) +16 cos 4 COS(1/6) + 8 cos(1) 5(1)] = 8 = (rounded to six decimal places) Therefore, using the Trapezoidal Rule with n = 4 and rounding to six decimal places we have 1 √² 8 cos(x²) dx =
Transcribed Image Text:This gives us TA 1 8 cos(0) + 16 cos( os() +16 cos COS(1) +16 cos 4 COS(1/6) + 8 cos(1) 5(1)] = 8 = (rounded to six decimal places) Therefore, using the Trapezoidal Rule with n = 4 and rounding to six decimal places we have 1 √² 8 cos(x²) dx =
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