[4thITEM] *refer to the photo below* Three liquids that will not mix are poured into a cylindrical container. The volumes anddensities of the liquids are 0.761 L, 3. 13 g/cm'; 1. 14 L, 1. 21 g/cm'; and 0. 305 L,0.608 g/cm. What is the force on the bottom of the container due to these liquids? Oneliter = 1L= 1000 cm'. (Ignore the contribution due to the atmosphere.) The tolerance is+ 1 in the 3rd significant digit.Numer:Units: N

Given Density D1 = 3.13 g/cm3 =3130 kg/m3 D2= 1.21 g/cm3 = 1210 kg/m3 D3= 0.608 g/cm3 =608 kg/m3…

Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are 0.761 L, 3. 13 g/cm; 1.14 L, 1. 21 g/cm; and 0. 305 L, 0.608 g/cm². What is the force on the bottom of the container due to these liquids? One liter = 1 L = 1000 cm. (Ignore the contribution due to the atmosphere.) The tolerance is + 1 in the 3rd significant digit. Numer: Units: N

Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are 0.761 L, 3. 13 g/cm; 1.14 L, 1. 21 g/cm; and 0. 305 L, 0.608 g/cm². What is the force on the bottom of the container due to these liquids? One liter = 1 L = 1000 cm. (Ignore the contribution due to the atmosphere.) The tolerance is + 1 in the 3rd significant digit. Numer: Units: N

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter13: State Of Matter

Section: Chapter Questions

Problem 94A

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