Tryptamine is an aromatic compound. In its structure below, highlight the atom with the lone pair in red if the lone pairoccupies a p orbital, blue if it occupies an sp orbital, or green if it occupies an sp orbital.3HNH₂G

Tryptamine is a fascinating aromatic compound commonly studied for its structural attributes and its…

Answered: Tryptamine is an aromatic compound. In…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter17: Conjugation And Molecular Orbital (mo) Theory

Section: Chapter Questions

Problem 10E

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What is the major difference between an antiaromatic and aromatic compound? Antiaromatic compounds have at least one sp³ hybridized atom in the ring. Antiaromatic compounds are not conjugated. Only aromatic compounds have 4n+ 2 pi electrons. The structure must be cyclic for aromatic but not antiaromatic compounds. Aromatic, not Antiaromatic compounds, are planar.
Specify whether the two structures are resonance contributors to the same resonance hybrid. Be sure to explain your reasoning. If yes, be sure to specify which is preferred and why. H2C=NH2
LYRICA (pregabalin) is an oral pharmaceutical primarily indicated for the management of fibromyalgia and neuropathic pain. At a pH of 11, LYRICA has an overall charge of –1, with most atoms neutral and only one oxygen showing a –1 formal charge. The structure for LYRICA at pH 11 is shown below. Add all the missing lone pairs to the given structure of LYRICA.
Define Protons on Carbon-Carbon Triple Bonds ?
Which is a correct statement about the three planar aromatic ring compounds, C4H42, C5H5, C6H6? O They are all incorrect. O They are all correct. O C4H42 has a quadruply degenerate second energy level. O C5H5 has a 5-degenerate second energy level. O CoHo has a 6-fold degenerate second energy level.
3) How many electrons are delocalized in how many p-orbitals? Draw the most and second most stable resonance structures of the following compound. Order the structures by increasing stability. What is the partial charge distribution in the resonance hybrid?
Nicotine present in tobacco has the following structure. Which nitrogen is more basic and explain your choice. CH3 2 ○ N1 is more basic as it is sp2 hybridized and more electronegative because of less S character. O N2 is more basic as it is sp3 hybridized and less electronegative because of less S character. ON1 is more basic as its lone pair has resonance.
Une or more valid answers. Explain the answers. The localization or resonance energy: a) Justify the increased stability of molecules that have unlocated electrons b) It is a consequence of the mobility of the electrons that form the “sigma” bonds c) It occurs in compounds with conjugated double bonds, but not in aromatic compounds d) It is shown by the experimental values of the enthalpies of formation.
Briefly explain why the aromatic hydrocarbon azulene, C10H8, possesses a significant dipole moment. Use diagrams as needed to illustrate/clarify your answer.
In the sketch of the structure of SO2 label all bonds. Drag the appropriate labels to their respective targets. Labels can be used once, more than once, or not at all. : S(p) – O(p) Lone pair in p orbital Lone pair in sp? orbital o : S(p) – 0(sp²) т: S(p) — О(p) T: S(sp²) – O(p) r: S(sp²) – O(p) S(p) – O(sp²)
4. One of the resonance structures of "tropylium ion" (C7H7*) is shown below. It is planar and aromatic with Hückel number of p-n electrons where n=1. Draw all the other contributing resonance structures. (There are more than two.) Based on the “average" of the contributing resonance structures, how close does the average ring carbon get to its "octeť" in tropylium ion?
For each of the following pairs of resonance structures, cirele the one that would make greater contribution to the actual resonance hybrid. OCH, OCH, A- BI E =

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Tryptamine is an aromatic compound. In its structure below, highlight the atom with the lone pair in red if the lone pair occupies a p orbital, blue if it occupies an sp orbital, or green if it occupies an sp orbital. 3 H NH₂ G