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Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cr³+ (aq) + 21 (aq) → 2Cr²+ (s) + 12 (s) From the table of standard reduction potentials: = = 0.535 V ECr³+/Cr²+ = -0.410 V, E₂/1- Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGO for this reaction would be ✓than zero.

Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cr³+ (aq) + 21 (aq) → 2Cr²+ (s) + 12 (s) From the table of standard reduction potentials: = = 0.535 V ECr³+/Cr²+ = -0.410 V, E₂/1- Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGO for this reaction would be ✓than zero.

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.108QE: At 298 K, the solubility product constant for solid Ba(IO3)2 is 1.5 109. Use the standard reduction...
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Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cr³+ (aq) + 21¯¯ (aq) → 2Cr²+ (s) + I₂ (s) From the table of standard reduction potentials: = -0.410 V, Ex = 0.535 V ECr³+/Cr²+ 1₂/I- Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGO for this reaction would be than zero.
Transcribed Image Text:Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cr³+ (aq) + 21¯¯ (aq) → 2Cr²+ (s) + I₂ (s) From the table of standard reduction potentials: = -0.410 V, Ex = 0.535 V ECr³+/Cr²+ 1₂/I- Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGO for this reaction would be than zero.
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