use wildcard mask to match host. Work out the wildcard masks for the following IP subnets: a. 192.168.0.0 - 192.168.1.255 b. 172.16.2.0 - 172.16.2.31 c. 12.34.32.0 - 12.34.63.255 d. 11.22.16.0 - 11.22.31.255 e. 160.160.160.160 - 160.160.160.167
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ACLs use wildcard mask to match host. Work out the wildcard masks for the following IP subnets:
a. 192.168.0.0 - 192.168.1.255
b. 172.16.2.0 - 172.16.2.31
c. 12.34.32.0 - 12.34.63.255
d. 11.22.16.0 - 11.22.31.255
e. 160.160.160.160 - 160.160.160.167
Step by step
Solved in 2 steps
- For the following Ips, write the network name, BC address, Prefix length, and thedefault maskNet name BC Prefix length default mask 11.45.3.5 180.90.27.89 190.35.177.98 192.76.19.1 200.30.50.90 100.100.100.100 107.39.50.20 192.3.5.6 DHCP Consider the below topology STAFF01 192.168.1.0/24 NS Server STAFFN 172.16.0.1 STAFF02 192.168.1.254 192.168.2.0/24 192.168.3.254 - 172.16.0.254 - OUTER SERVERSN ADMIN LAN ADMINO1 Active Drectory 192.168.2.254 172.16.0.2 GUESTO2 192.168.2.0/24 GUEST LAN DHCP Server GUESTO1 172.16.0.3 How many scopes should be installed on the DHCP server? * Your answer What is the size of the IP Ilease that should be set on the Staff LAN? * Your answerMC9: In wireless LAN communication, MACA is widely used. In this protocol, in order to avoid collision, a sender can send sender is granted the privilege to send a frame to the receiver only after it receives request signal to a receiver. The replied from the receiver. RTS, RTS CTS, CTS RTS, CTS CTS, RTS
- Host IP Address: Original Subnet Mask New Subnet Mask: Given: Find: Number of Subnet Bits Number of Subnets Created Number of Host Bits per Subnet Number of Hosts per Subnet Network Address of this Subnet IPv4 Address of First Host on this Subnet IPv4 Address of Last Host on this Subnet IPv4 Broadcast Address on this Subnet 192.135.250.180 255.255.255.0 255.255.255.248Calculate IPV4 Address Subnets in the following given Table. Given: Host IP address: Default Subnet Mask: 255.255.255.0 196.168.10.0 New Subnet Mask: 255.255.255.192 Determine: Number of Subnets Created: per Subnet: Network Address of this Subnet: Number of Hosts IPV4 Address of First Host on this Subnet: IPV4 Broadcast Address on this Subnet:The diagram below Bustrates a NAT-enabled router connecting a LAN to the Internet. The IP addresses of the router's LAN and Internet interfaces are shown (H2) src 192.168.30.10: 2500 dst 134.210.1.99 : 80 192.168.30.1 140.62.1.8 src 192.168.30.20: 2500 dst 134.210.1.99 80 src= dst Internet src dst (A) (B) (E) (F) : ___(C)_ : _(D)__ : ____(G)__ : The two host computers are each sending a packet to the same web server on the Internet Show the changes made by NAT to the IP addresses and port numbers of each packet as they are sent (provide your own sample values in coses where the actual values cannot be defined) An Save and Sub
- a- Given the following screenshot, some errors are preventing PC-C from accessing the Redundant Internet Connection. Find the errors and correct them. Router0(config)# ip route 0.0.0.0 0.0.0.0 209.0.0.1 Router1(config)# router rip Router0(config)# router rip Router1(config-router)# passive-interface s0/0/1 Router0(config-router)# network 172.16.1.4 Router1(config-router)# network 172.16.1.0 Router0(config-router)# auto-summary Router1(config-router)# no auto-summary Your answer b- After correcting the errors, PC-C is able to reach the Primary Internet. Which command is used to view the routing table on Router 1?* Your answerq28- A router interface has been assigned an IP address of 182.18.192.166 with a mask of 255.255.255.224. To which subnet does the IP address belong? Select one: A. 182.18.192.168 B. 182.18.192.0 C. 182.18.192.128 D. 182.18.192.160 E. 182.18.0.0Find the address in all networks. Subnets =1000. Hosts =60 Address = 165.100.0.0. class- 0 -127 128- 191 Write down the default subnet mask and customized subnet mask. Def = 255.255.0.0 1111 1111. 1111 1111. 1111 1111. 1100 0000 -> 255.255.255.192 2^ 6= valid ip addresses 64 hosts -2 62 hosts 165.100.0.0 - 165.100.0.1 TO 165.100.0.62 165.100.0.63 => 64 165.100.0.64 - 165.100.0.128 165.100.0.192 165.100.0.193 to 165.100.0. 254 165.100.0.255 What is the 10th subnet range? Find the 4th subnet DBA. Determine the assignable addresses for 4th subnet range Give the 15th subnet id and the last host address in the 3rd subnet Give the CIDR notation.
- IKT204-G H21, IP miscellaneous 14 Only one of the claims below is correct, the others are wrong or meaningless. Select the correct alternative. Select one alternative: If two IP datagrams containing segments to a TCP connection are received in the wrong order, the router will reorganize them so that they are forwarded in correct order. O The smallest header size of IPV4 is 20 bytes, but it may be larger. When an IP datagram is discarded in a router due to overload, then the router will send an ICMP message back to the sender, so that the IP protocol can retransmit the datagram. If the traffic load in a router is too large, then it will reduce its Receive Window, and use ICMP to warn all senders about the new and smaller Receive Window.VLSM A company has an IP rage of 10.1.128.0/19. Provide step by step to divide the company networks into the following subnets: Management team: 50 hosts • Head quarter office: 1100 hosts • Manufacturing site: 1024 hosts • 1st branch 300 hosts 2nd branch 255 hostsDetermine whether or not the following IPv6 address notations are correct:•::0F53:6382:AB00:67DB:BB27:7332•7803:42F2:::88EC:D4BA:B75D:11CD•::4BA8:95CC::DB97:4EAB•74DC::02BA•::00FF:128.112.92.116
