void print_factors (int x), that print the prime factors of x's. int sum (int x, int y), that find the summation of odd numbers ending with 7 between x & y. void print_prime (int n) ,that generates n numbers any print any prime number between them. void fact (int n, ref int f),that find the fact number of n( f = n!).

void print_factors (int x), that print the prime factors of x's. int sum (int x, int y), that find the summation of odd numbers ending with 7 between x & y. void print_prime (int n) ,that generates n numbers any print any prime number between them. void fact (int n, ref int f),that find the fact number of n( f = n!).

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter11: Inheritance And Composition

Section: Chapter Questions

Problem 14PE

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- Q3: Write the following functions: void print_factors (int x), that print the prime factors of x's. int sum (int x, int y), that find the summation of odd numbers ending with 7 between x & y. void print_prime (int n),that generates n numbers any print any prime number between them. void fact (int n, ref int f),that find the fact number of n( f = n!).
Let 1 represent true and 0 represent false. The function Conjunction(), whose incomplete code is given below, computes p∧q: def Conjunction(p,q):#FIX ME#return 1else:return 0 What should the line of code which contains the expression #FIX ME# be replaced with in order to complete the code? Question 3 options: if p != q: if p == 0 and q == 0: if p == q: if p == 1 and q == 1:
3. Find Relatively Prime Write a function to return a number that is relatively prime with the given number. /* return an integer that is relatively prime with n, and greater than 1i.e., the gcd of the returned int and n is 1 Note: Although gcd(n,n-1)=1, we don't want to return n-1*/int RelativelyPrime (int n) 4. Find Inverse Then implement the following function, which returns the inverse modulo, and test it.Note that you need to check whether a and n are relative prime before calling thisfunction. Recall that a and n are relatively prime means that gcd(a,n)=1, i.e., theirgreatest common divisor is 1. Also recall that the extended Euclidean Algorithm canfind the integer s and t for a and n such that as+nt=gcd(a,n), where s is the inverseof a modulo n. /* n>1, a is nonnegative *//* a<=n *//* a and n are relative prime to each other *//* return s such that a*s mod n is 1 */int inverse (int a, int n){int s, t;int d = ExtednedEuclidAlgGCD (n, a, s, t);if (d==1){return (mod (t,…
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Prompt: When someone calls you on the phone, he or she looks up your number in a phone book (a function from names to phone numbers). When Caller ID shows who is calling, it has performed the inverse function, finding the name corresponding to the number. Explain why this situation represents an application of inverse of a function in familiar situations.
Define stubs for the functions get_user_num() and compute_avg(). Each stub should print "FIXME: Finish function_name)" followed by a newline, and should return -1. Each stub must also contain the function's parameters. Sample output with two calls to get_user_num() and one call to compute_avg(): FIXME: Finish get_user_num() | FIXME: Finish get_user_num() FIXME: Finish compute_avg() Avg: -1 354684.2266598.qx3zgy7 2 Your solution goes here ''' 4 user_num1 5 user_num2 6 avg_result get_user_num() get_user_num) compute_avg(user_num1, user_num2) 8 user_num1 9 user_num2 10 avg_result %3D 11 12 print('Avg:', avg_result)
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2. Extract Hours and Minutes(with Boilerplates) by Catherine Arellano Write a program that will accept an integer value from 0000 to 2359. It will then extract the first 2 values of the integer to be the hours, and the last 2 to be the minutes. Implement the following functions: int findHour(int time); /* computes and returns hours.*/ int findMin(int time); /* computes and returns minutes.*/ void display (int hour, int min); /*display the hours and minutes*/ Note: You are not allowed to edit main.c and Time.h. Input A time in format HHMM 9 16
A pentagonal number is defined as for and so on. So, the first few numbers are 1, 5, 12, 22, .... Write a function with the following header that returns a pentagonal number:def getPentagonalNumber(n):Write a test program that uses this function to display the first 100 pentagonal numbers with 10 numbers on each line.
Define stubs for the functions get_user_num() and compute_avg(). Each stub should print "FIXME: Finish function_name()" followed by a newline, and should return -1. Each stub must also contain the function's parameters.Sample output with two calls to get_user_num() and one call to compute_avg(): FIXME: Finish get_user_num() FIXME: Finish get_user_num() FIXME: Finish compute_avg() Avg: -1 ''' Your solution goes here ''' user_num1 = 0user_num2 = 0avg_result = 0 user_num1 = get_user_num()user_num2 = get_user_num()avg_result = compute_avg(user_num1, user_num2) print('Avg:', avg_result)
***in python only*** use turtle function Define the concentricCircles function such that: It draws a series of concentric circles, where the first parameter specifies the radius of the outermost circle, and the second parameter specifies the number of circles to draw. The third and fourth parameters specify an outer color and an other color, respectively. The outer color is used for the largest (i.e., outermost) circle, and then every other circle out to the edge alternates between that color and the 'other' color. The difference between the radii of subsequent circles is always the same, and this difference is also equal to the radius of the smallest circle. Put another way: the distance between the inside and outside of each ring is the same. Define concentricCircles with 4 parameters Use def to define concentricCircles with 4 parameters Use any kind of loop Within the definition of concentricCircles with 4 parameters, use any kind of loop in at least one place. Call…