PLEASE ANSWER CORRECTLY THANK YOU Water is asolvent for HCIO4, HCI, and nitric acids because all three are completelyionized in water.a. Differentiatingb. LevelingC. Proticd. Aprotice. None of the above What is the relationship between Ka and Kb for a conjugate acid-base pair in aqueoussolution?a. Ka x Kb = KWb. Ka + Kb = KWC. Ka / Kb = KWd. Ka + Kb – KW = 1.0e. None of the above%3D%3D%3D

Answered: Water is a ionized in water. solvent…

Water is a ionized in water. solvent for HCIO4, HCI, and nitric acids because all three are completely a. Differentiating b. Leveling C. Protic d. Aprotic e. None of the above

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter20: Applications Of Oxidation/reduction Titrations

Section: Chapter Questions

Problem 20.2QAP

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Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Question

PLEASE ANSWER CORRECTLY THANK YOU

Water is a
solvent for HCIO4, HCI, and nitric acids because all three are completely
ionized in water.
a. Differentiating
b. Leveling
C. Protic
d. Aprotic
e. None of the above

What is the relationship between Ka and Kb for a conjugate acid-base pair in aqueous
solution?
a. Ka x Kb = KW
b. Ka + Kb = KW
C. Ka / Kb = KW
d. Ka + Kb – KW = 1.0
e. None of the above
%3D
%3D
%3D

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