What are the magnitude and direction of the electric field whose force will balance the weight of the following? (Use the information in the table below). Particle Charge (C) Mass (kg) Electron (e) -1.6021765 × 10-19 9.1094 x 10-31 Proton (p) +1.6021765 x 10-19 1.67262 x 10-27 Neutron (n) 1.67493 x 10-27 (a) an electron N/C Direction (b) a proton N/C) Direction

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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
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Chapter30: Atomic Physics
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Problem 4CQ: What two pieces of evidence allowed the first calculation of me, the mass of the electron? (a) The...
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Chapter 22

What are the magnitude and direction of the electric field whose force will balance the weight of the following? (Use the information in the table below).
Particle
Charge (C)
Mass (kg)
Electron (e)
-1.6021765 x 10-19
9.1094 x 10-31
Proton (p)
+1.6021765 x 10-19
1.67262 x 10-27
Neutron (n)
1.67493 x 1027
(a) an electron
N/C) Direction
(b) a proton
N/C
Direction
Transcribed Image Text:What are the magnitude and direction of the electric field whose force will balance the weight of the following? (Use the information in the table below). Particle Charge (C) Mass (kg) Electron (e) -1.6021765 x 10-19 9.1094 x 10-31 Proton (p) +1.6021765 x 10-19 1.67262 x 10-27 Neutron (n) 1.67493 x 1027 (a) an electron N/C) Direction (b) a proton N/C Direction
Expert Solution
Step 1

Since the electric force is balanced by the weight of the particle, So 

Fe=WqE=mgE=mgq

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