Answered: What does the counter1 provide at the…

What does the counter1 provide at the end of this script? x=[ 30 e e 2 1 -1 -2 -3]; counter1=0; counter2=0; for i=1:length(x) if x(i)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

in c++ Magic Decoder Ring. A one-time pad is a coding device that uses each character of a key string only once to encode and decode a corresponding character in a message string. Thus, the first character in the key is used to encode and decode the first character in the clear message, the second character in the key is used with the second character in the message, etc. No portion of the key is reused in subsequent messages, making for a very solid coding system, assuming a randomly generated key. You will need to create a class titled MagicDecoderRing that contains the variables and functions needed for obtaining the clear and key texts, encoding and decoding the messages, writing out the encoded message etc. You will need to instantiate an instance of this class in your main function to run your program and encode and decode messages. You need to further break your MagicDecoderRing code down into many small functions that each can be described with a single sentence without ‘ands”…
in C++ generate a histogramLinks to an external site. of 20,000 randomly generated integer numbers according to a normal distribution with a user-specified mean and standard deviation. Your histogram will include the frequencies of at least 9 data points centering at the mean value: mean +/- x*stdDev, where x is in {0, 1, 2, 3, 4}. For example, given mean=1 and standard deviation of 2, you will calculate the frequency of at least the following values: 1-4*2, 1-3*2, 1-2*2, 1-2, 1, 1+2, 1+2*2, 1+3*2, 1*4*2.
Write down a program for summing up the total vehicle trip counts between a source location and destination location where each trip data has to get from the user where each trip data is in the following format: SourceLocationID-DestinationLocationID:Trip Counts The output must be sorted based on the Source Location ID Input Format 402-401:15 401-404:05 404-401:03 402-401:15 401-404:09 402-401:15 401-404:15 404-401:03 405-404:03
Problem Y: Implement the reader writer problem using pthreads and semaphores. You should allow multiple readers to read at the same time and only one single writer to write to the data set. You are required to use the following: 1. A semaphore rw_muter initialized to 1. 2. A semaphore muter initialized to 1. 3. An integer reader_count initialized to 0.
Q2: Design a PDA for accepting a language {0^1m0n | m, n>=1} give the ID form as we explain in the lecture. Apply the string "00011000" on this PDA using ID transitions.
1. Build PDA to generate all strings of the form 0n12n+3 where n>=0 2. Build CFG to generate all strings of the form 0n12n+3 where n>=0 3. Build PDA to generate all strings of the form 0n1 n where n is even 4. Build CFG to generate all strings of the form 0n1 n where n is even 5. Build PDA to generate all strings of the form 1 n 0 m, where m and n are even, and m>n 6. Build CFG to generate all strings of the form 1 n 0 m 1 n, where m and n are greater or equal to 0. 7. Build PDA to generate all strings of the form w11, where w is a palindrome containing 1's and 0's. For example, the following strings should be generated: • 01011 (010 is a palindrome, and 11 is the ending) • 1101111 (11011 is a palindrome, and 11 is the ending) • 01011 (010 is a palindrome, and 11 is the ending) 8. Build CFG to generate all strings of the form w11, where w is a palindrome containing 1's and 0's. 9. Build PDA which generates all non-empty strings with equal number of 1’s and 0’s \ 10. Please…
in C++ language Magic Decoder Ring. A one-time pad is a coding device that uses each character of a key string only once to encode and decode a corresponding character in a message string. Thus, the first character in the key is used to encode and decode the first character in the clear message, the second character in the key is used with the second character in the message, etc. No portion of the key is reused in subsequent messages, making for a very solid coding system, assuming a randomly generated key. You will need to create a class titled MagicDecoderRing that contains the variables and functions needed for obtaining the clear and key texts, encoding and decoding the messages, writing out the encoded message etc. You will need to instantiate an instance of this class in your main function to run your program and encode and decode messages. You need to further break your MagicDecoderRing code down into many small functions that each can be described with a single sentence…
In C++ language Magic Decoder Ring. A one-time pad is a coding device that uses each character of a key string only once to encode and decode a corresponding character in a message string. Thus, the first character in the key is used to encode and decode the first character in the clear message, the second character in the key is used with the second character in the message, etc. No portion of the key is reused in subsequent messages, making for a very solid coding system, assuming a randomly generated key. You will need to create a class titled MagicDecoderRing that contains the variables and functions needed for obtaining the clear and key texts, encoding and decoding the messages, writing out the encoded message etc. You will need to instantiate an instance of this class in your main function to run your program and encode and decode messages. You need to further break your MagicDecoderRing code down into many small functions that each can be described with a single sentence…
Consider the code C={00010, 01100,01011,11010,01010}. What is the minimum distance of C? For what k is the code C k-error detecting? Write the set of error patterns that C can detect?
function result = result = ''; 1 tokens_to_str_code(token_mat, time_unit) 3 for i =1:size(token_mat,1) 4 5 if(token_mat (i,1) if(token_mat(i,2) > 4*time_unit) result = strcat(result,"-"); elseif((token_mat(i,2) > time_unit) && (token_mat(i,2) 8*time_unit) result = strcat(result,"/"); elseif((token_mat(i,2) 11 == 0) 12 13 14 4*time_unit) && (token_mat(i,2) < 8*time_unit)) 15 result strcat(result," "); %3D 16 end 17 end 18 end 19 end 20 21 Check Test Expected Got tokens %3D [1 4; е 3; 1 3; е 1; 1 3; е 1; 1 1; ө 1; 1 1 ]; time_unit = .5; disp( tokens_to_str_code( tokens, time_unit )) tokens = [ 0 4; 1 1457; 0 463; 1 1457; 0 463; 1 497; 0 1423; 1 1457; ---/..--.. --.---/..--.. о 463; 1 1457; 0 463; 1 1457; ө 3343; 1 497; ө 463; 1 497; 0 463; 1 1457; 0 1423; 1 1457; 0 463; 1 497; 0 463; 1 497; e 379 ]; time_unit = 240; disp( tokens_to_str_code( tokens, time_unit ))
I need the code in C programing i am begging you please. There are several test cases. Each test case begins with a line containing a single integer n (1≤n≤1000). Each of the next n lines is either a type-1 command, or an integer 2 followed by an integer x. This means that executing the type-2 command returned the element x. The value of x is always a positive integer not larger than 100. Given a sequence of operations with return values, you’re going to guess the data structure. It is a stack (Last-In, First-Out), a queue (First-In, First-Out), a priority-queue (Always take out larger elements first), not sure(It can be more than one of the three data structures mentioned above) or impossible(It can’t be a stack, a queue or a priority queue). Sample Input Sample output 6 1 1 1 2 1 3 2 1 2 2 2 3 6 1 1 1 2 1 3 2 3 2 2 2 1 2 1 1 2 2 4 1 2 1 1 2 1 2 2 7 1 2 1 5 1 1 1 3 2 5 1 4 2 4 1 2 1 queue not sure impossible stack priority queue impossible
What are the values of PB0-7 and PD0-7 after the following code segment executes? unsigned char w = 0x35; DDRB = 0X0F; DDRD OX0F %3D PORTB = w & OX0F; PORTD = w >>4; P87 P86 PB5 P84 PB3 PB2 PB1 PBO 000 0 010 1 b010 101 0 1 1001 1 001 PD7 PD6 PDS PD4 PD3 PD2 PD1 PDO 0000 001 1 001 1 001 1 10 10 1 01 d000 0000 01 1 Select one: а. а b. b С. с d. d е. е