What is the power factor for the circuit in the figure below? Given: R = 250 0, L = 750 mH
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- 60. Design a circuit to limit a 20 V rms sinusoidal voltage to a maximum positive amplitude of 10 V and a maximum negative amplitude of -5 V using a single 14 V de voltage source. 61 Datermine the volto in the girRuit F Figura 1 1?can you please give me the comple solution for this question, thanks. A certain voltage function contains a constant term, a fundamental and third harmonic. The maximum value of the fundamental is 85 % of the constant term and the maximum value of the third harmonic is 55 % of the constant term. If the effective value of this function is 180.3V, find the magnitude of the two harmonics. A.IstHarmonic = 75 V , 3rd Harmonic = 120V B. Ist Harmonic = 80 V , 3rd Harmonic = 125V C. IstHarmonic = 120 , 3rd Harmonic = 75V D. Ist Harmonic = 125 V , 3rd Harmonic = 80V E. NOTAAn rms voltage of 22.2 V with a frequencyof 1.00 kHz is applied to a 0.290-mH inductor. (a) What is the rmscurrent in this circuit? (b) By what factor does the current changeif the frequency of the voltage is doubled? (c) Calculate the current for a frequency of 2.00 kHz
- The rms value of the resultant current in a wire carries a dc current of 10 A and a sinusoidal alternating current of peak of value 20 A is-The peak to peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 9 cm and the 'volts/cm' switch is on 25 V/cm. The peak voltage is given by O 2.78 V O 159.07 V O 112.50 V O 225.00 VDetermine the rms current in the figure for Vrms = 16 V and C = 74µF V f=10 kHz
- In an experiment, the function generator is adjusted to generate a square voltage at a certain frequency. This voltage is displayed on an oscilloscope and the reading is 16 V peak-to-peak. The rms value of this voltage is .What will be the rms value of this voltage if the frequency is doubled? Select one: O 16 Vrms 32 Vrms O 8 Vrms . 8 Vrms ..... O 5.657 Vrms 5.657 Vrms ....... O 8 Vrms . 16 Vrms O 16 Vrms 8 Vrms ......The 60 Hz AC source and 240 V rms voltage provides a power of 5000 VA for a load with a lagging power factor of 0.85. Determine the reactive power in the capacitor and the value of the capacitor that must be connected in parallel with the load to bring the power factor to 0.92 inductiveShown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…
- For the following parts, identify the name of each circuit, plot the output waveform, and find the DC output average voltage. Part (a) V 1 cycle V₁ = V sin cor Part (b) PE Part (c) Vm Vi ele eeeeeeeeeeeeee D D₂ D₁ D₂ R Va + D₂ D₁A sinusoidal voltage is applied to the resistive circuit in the given figure. Determine current peak or Ip. find Irms , find Iaverage , find Ip-pWhat is the frequency (in Hz) of the figure below? 250 us