What volume in liters of fluorine gas is needed to form 999 L of sulfur hexafluoride gas if the following reaction takes place at 2.00 atm and 273.15 K: S(s) + 3F₂(g) → SF₆ (g)

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Q: What volume in liters of fluorine gas is needed to form 455 L of sulfur hexafluoride gas if the…

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Q: How many liters of fluorine gas are needed to form 683 L of sulfur hexafluoride gas if the following…

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Q: What volume in liters of fluorine gas is needed to form 103 L of sulfur hexafluoride gas if the…

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Q: If 45.0 g of calcium carbide is allowed to react with an excess amount of water, what will be the…

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Q: What volume in liters of fluorine gas is needed to form 683 L of sulfur hexafluoride gas if the…

A: Data given,  Volume of sulfur hexafluoride, V = 683 L  Pressure of the reaction, P = 2.00 atm…

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Q: How many liters of fluorine gas is needed to form 999 L of sulfur hexafluoride gas if the following…

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Q: A 4.17 g4.17 g sample of NH3NH3 gas and a 4.17 g4.17 g sample of HClHCl gas are mixed in a 2.00…

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Q: How many liters of fluorine gas are needed to form 799 L of sulfur hexafluoride gas if the following…

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Q: What is the volume in liters of hydrogen gas that would be produced by the reaction of 40.6 g of Al…

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Q: How many liters of fluorine gas are needed to form 303 L of sulfur hexafluoride gas if the following…

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Q: What volume in liters of fluorine gas is needed to form 475 L of sulfur hexafluoride gas if the…

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Q: What volume in liters of fluorine gas is needed to form 863 L of sulfur hexafluoride gas if the…

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.