What would justify the following ratio appearing after phenotyping the outcome of a crossing trial: 8.9: 2.9: 3.2:1? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b d Obviously this represents independent assortment based on crossing dihybrid heterozygotes. Obviously this represents gene linkage based on test crossing a dihybrid heterozygote. Obviously this represents the results of a trihybrid test cross. Obviously this represents independent assortment based on crossing monohybrid heterozygotes.

What would justify the following ratio appearing after phenotyping the outcome of a crossing trial: 8.9: 2.9: 3.2:1? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b d Obviously this represents independent assortment based on crossing dihybrid heterozygotes. Obviously this represents gene linkage based on test crossing a dihybrid heterozygote. Obviously this represents the results of a trihybrid test cross. Obviously this represents independent assortment based on crossing monohybrid heterozygotes.

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Description: What would justify the following ratio appearing after phenotyping the outcome of a crossingtrial: 8.9: 2.9: 3.2:1?Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.abCdObviously this represents ind

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

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Individuals of genotype AaBb were mated to individuals of genotype aabb. One thousand offspring were counted, with the following results: 474 Aabb, 480 aaBb, 20 AaBb, and 26 aabb. What type of cross is it? Are these loci linked? What are the two parental classes and the two recombinant classes of offspring? What is the percentage of recombination between these two loci? How many map units apart are they?
Consider these two crosses and assume that independent segregation is exhibited by all gene pairs: RrmmTT x RRMmTtFfGg x FfGg Derive the gametic ratio of the second parent in each cross using the branching method. What proportion of the offspring in each cross will be heterozygous for all gene pairs? Derive the genotypic ratio for the offspring from each cross using the branching method. Show complete solutions.
A large ear of corn has a total of 433 grains, including 271 purple & smooth, 73 purple & shrunken, 63yellow & smooth, & 26 yellow & shrunken. Conduct a X^2 analysis to determine if this ear of corn was produced by adihybrid cross (PpRr x PpRr) resulting in a phenotypic ratio of 9:3:3:1.
DIHYBRID CROSS Heterozygous Yellow and heterozygous round seed crossed with homozygous yellow and heterozygous round seed. Find the following: 1. Alleles of both parents (given problems) 2. Genotype 3. Phenotype ratio 4. Write the punnet square -Please answer this on the paper and explain the answer step by step. Thank you asap
A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous wild type male. The resulting progeny were allowed to mate with one another to produce the data set. Three repetitions of the experiment were conducted. The following data were produced from the crosses. Test these data to determine if they are significantly different from the expected phenotypic ratio. Use the 5% level of significance. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject for each experiment. Wild eye Wild body – 112, Wild eye Ebony body – 40, Sepia eye Wild body – 35, Sepia eye Ebony body – 11
Table 2 below shows the banding pattern for a cross between parents P1 and P2 producing the 6 progeny I1-6. The parents are double heterozygotes for two independently assorting genes. Identify the pairs of bands that correspond to the two segregating pairs of alleles. Assuming independent assortment, what is the probability that an offspring shows the pattern observed in I5. Table 2 RFLP data Size (kb) P1 P2 I1 I2 I3 I4 I5 I6 5.5 X X X X X X 3.5 X X X X X X X 2.5 X X X X X 2 X X X X X
In onion, male sterility is produced when the nuclear genotype is aa and the mitochondrial gene S (sterile) are present. Any other combination of nuclear genotype and mitochondrial gene (including gene F for fertile) will result in a male fertile plant. Give the genotypic ratio and the phenotypic ratio or the percentage of male sterile and male fertile offspring that will be produced in the following crosses. 1. Aa + S male x aa + F female 2. Reciprocal cross of number 1. (Note that when we do reciprocal cross, we interchange/swap the genotypes of the parents (if there is a nuclear gene involved, you interchange the nuclear genotype as well). 3. Aa + S female x Aa + F male 4. Reciprocal cross of number 3.
pt pt PT PPTt purple tall PpTt purple tall Pt Pptt purple white Pptt purple white Using any two plants resulting from your test cross (even two of the same genotypes if you would prefer), perform a second cross. Provide a Punnett square demonstrating this dihybrid cross.What are the ratios for each genotype in the resulting offspring? What are the ratios for each phenotype? Your answer should clearly indicate the genotype and phenotype each portion of the ratio is referring to
Kernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of each offspring with the following genotypes: (Note: 4 alleles – red; 3 – medium red; 2 – intermediate red; 1 – light red; 0 – white). CAPITAL letters only and with spaces when applicable. AABb - AaBb - AABB - aaBb - aabb -
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Consider the following dihybrid testcross: B/b • E/e × b/b • e/e For the progeny from this testcross, determine the relative proportions (from 0% to 100%) of each genotype if the two genes: a) are linked (dominant alleles in cis conformation) with no crossing over: Be/be: be/be: BE/be: bE/be: b) assort independently. B/b; E/e: B/b; e/e: b/b; E/e: b/b; e/e: c) are linked (dominant alleles in cis conformation) and 20 map units apart. Be/be: be/be: BE/be: bE/be: