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What do the peaks of C6H12O2 show?
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- Problem 6 C-H IR Spectrum quid fm گرد 1716 4000 3000 2000 1600 1200 112 800 (cm") 100 80 43 Mass Spectrum UV Spectrum 60 Amas 289 nm (log, 1.4) solvent methan CHO2 40 80 120 160 200 240 280 m/e 1C NMR Spectrum (100 M. COC, solution) DEPT CH OHt ont proton decoupled Nvert 200 160 120 80 40 8 (ppm) H NMR Spectrum (200 M CDC, soluion) TMS 3. 10 8. 8 (ppm)115 Problem 9 3458 R-H) IR Spectrum (CO soktiory 4000 zn+l=3 3000 2000 1600 1200 800 v (cm') 100 80 Mass Spectrum 60 Mate banch M 118 1S) 40 No significant UV absorption above 220 nm 20- 103 CeH1402 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (100 O MHz CDCI, solution) -1-14 =zaro DEPT CH CH, CH proton decoupled solvent 200 160 120 80 40 8 (ppm) 'H NMR Spectrum (200 MHz. CDCI, solution) Exchanges with D20 TMS 9. 4. 3 8 (ppm) 98 ead aseps 10The 'H NMR spectrum corresponds to an unknown compound with the molecular formula C,H,O. Deduce and draw the structure of the molecule. Draw the unknown compound. 1Η ΝMR Select Draw Rings More Erase 3 H C H 1 H||1 H 4.3 1 H 1 H (CH3)¼Si 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 0.5 0.0 6.0 5.5 5.0 300-MHz 'H NMR spectrum ppm (8)
- 110 Problem 4 IR Spectrum (CCI solution) menhsl propionate 1744 4000 3000 2000 1600 V (cm') 1200 800 100 57 80 29 Mass Spectrum 60 40 No significant UV absorption above 220 nm M*- 88 20 CAHBO2 40 80 120 160 m/e 200 240 280 13C NMR Spectrum (100.0 MHz. CDCI, solution) DEPT CH CH, CHt solvent proton decoupled 0. 8 (ppm) 120 80 40 200 160 H NMR Spectrum (200 MHz, CDCI, solution) expansion TMS ppm 1.0 2.0 4 8 (ppm 7 6. 10 % of base peakProblem 7 Mll IR Spectrum 2240 KBr dac) 4000 3000 2000 1600 1200 800 v (cm') 100 Mass Spectrum 80 60 63 40 No significant UV 40 M- 80 absorption above 220 nm 20 CAHAN2 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (100 O MHz, CDCI, solution) DEPT CH, CHt CH proton decoupled solvent 160 120 80 40 8 (ppm) 200 1H NMR Spectrum (400 MHz, CDCI, solution) TMS 6. 4 2 8 (ppm) 10 8 96 wad aseq jo116 Problem 10 IR Spectrum (KBr disc) 14=12+2 1693 4000 (02F14-8 2 CH2 3000 2000 1600 1200 B00 V (cm') 100 C=02 56 Mass Spectrum 80 M* 112 60 No significant UV absorption above 220 nm 40 20 CeHgO2 12+2-06/44 40 120 m/e 80 160 200 240 280 13C NMR Spectrum (100 O MHz. CDCI, solution) DEPT CH, CH,t CHt proton decoupled solvent 200 160 120 80 40 8 (ppm) H NMR Spectrum (400 MHz, CDCI, solution) TMS 1 8 (ppm 7 6. 4 3 2 10 9.
- hents ts 15 Consider the following structure. What is the multiplicity (splitting) of the B protons in the 1H NMR? 0 H₂C-C H₂ A C-H BI need help interpreting these 3 spectra, h-nmr,c-nmr, IR. All three correlate to same molecular structure. The question asks you to determine the molecular structure and label all peaks on all 3 spectra.1H NMR SpectraHow do I solve this?
- Determine the structure of C9H10O from the H NMR and IR spectra shown below. Question 3: Determine the structure of CHuO from the 'H NMR and IR spectra shown below. Problem R-7P CHO 300 MHz H NMR spectrum in CDCI, Source: Aldrich Spectra Viewer 33-09 tt Hz 30 20 10 0 ith 8.0 7.9 7.8 7.7 7.6 7.6 7.4 3.0 3.0 3.0 1.25 1.20 10 ppm Infrered Spectrum:4- How many proton signals appear in the 1H NMR spectrum of vinyl chloride? a) three signs b) two signs c) four signs 5- A compound with the general formula CHO showing one single signal in the NMR spectrum. The compound is: - a) 2--propanone b) cyclo propanol c) propanal| 6- a) m/e 66 b) m/e= 68 c) m/e= 69 The following compound is given by mass spectrometry, M.wt = 108, its peak at ....109 Problem 3 IR Spectrum (quid fim) 2084 1741 1243 4000 3000 2000 1600 1200 800 0.0 v (cm') 100 43 80 Mass Spectrum 0.5 60 UV spectrum 40 29 1.0아 solvent ethanol M= 88 130 20 15.4 mg/ 10 mis path length 1.00 cm CAHBO2 1.5 40 80 120 160 200 240 280 200 250 300 350 m/e 2 (nm) 13C NMR Spectrum (50.0 MHz. CDCI, solution) DEPT CH, CH, CHt proton decoupled solvent 200 160 120 80 40 0 8 (ppm) H NMR Spectrum (200 MHz, CDCI, solution) TMS 1 8 (ppm) 3 10 6. 8 7 92 % of base peak