Whenever they zig, you gotta zag def is_zigzag(n): A positive integer n is a zigzag number (also called an “alternating number” in some combinatorics materials) if the series of differences between
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Looking for assistance with this question:
Whenever they zig, you gotta zag
def is_zigzag(n):A positive integer n is a zigzag number (also called an “alternating number” in some combinatorics materials) if the series of differences between its consecutive digits read from left to right strictly alternates between positive and negative steps. The step from the 0irst digit to the second may be either positive or negative to start this dance. This function should determine whether its parameter n is a zigzag number.
In the negative examples in the table below, the part of the number that violates the zigzag property is highlighted in red.
|
n |
Expected result |
|
7 |
True |
|
25391 |
True |
|
90817263545463728185
|
True |
|
16329 |
False |
|
104175101096715
|
False |
|
49573912009 |
False |
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- please code in python You place a pawn at the top left corner of an n-by-n chess board, labeled (0,0). For each move, you have a choice: move the pawn down a single space, or move the pawn down one space and right one space. That is, if the pawn is at position (i,j), you can move the pawn to (i+1,j) or (i+1, j+1). Ask the user for the size of a chessboard, n (integer). Find the number of different paths starting from (0,0) that the pawn could take to reach each position on the chess board. For example, there are two different paths the pawn can take to reach (2,1). Look at the diagrams below to convince yourself of this. You can see the four paths that you can take by move 2. Start -> Move 1 -> Move 2 (0,0) -> (1,0) -> (2,1) (0,0) -> (1,0) -> (2,0) (0,0) -> (1,1) -> (2,1) (0,0) -> (1,1) -> (2,2) Print the board with the number of ways to reach each square labeled as shown below. For example: Enter a board size: 4 1 0 0 0 1 1 0 0 1 2 1 0 1 3 3 1Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a number and recursively determine how many of its digits are even. Return the count of the even digits in each number. % might prove useful to take the number apart digit by digit Sample Data : 453211145322224532714246813579 Sample Output : 23540Problem Description The hailstone sequence is defined as the integer sequence that results from manipulating a positive integer value n as follows: If n is even, divide it by 2 (using floor division) • If n is odd, multiply it by 3 and then add 1 Repeat this process until you reach 1. For example, starting with n = 5, we get the sequence 5, 16, 8, 4, 2, 1. If n is 6, we get the sequence 6, 3, 10, 5, 16, 8, 4, 2, 1. If n is 7, we get 7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1. If n is 8, we get the sequence 8, 4, 2, 1. As far as anyone can tell, this process will eventually reach 1 for any starting value, although mathematicians have been unable to formally prove this property as of yet. a. Write a Python function named hail () that takes a single integer argument. hail() should print out the sequence of numbers generated by applying the process above to the function parameter. This function does not return any value.
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- Tiling: The precondition to the problem is that you are given threeintegers n, i, j, where i and j are in the range 1 to 2n. You have a 2n by 2n squareboard of squares. You have a sufficient number of tiles each with the shape . Your goalis to place nonoverlapping tiles on the board to cover each of the 2n × 2n tiles except forthe single square at location i, j. Give a recursive algorithm for this problem in whichyou place one tile yourself and then have four friends help you. What is your base case?int n = 1; int k - 2; int r = n; if (k < n) { r - k6- You have two numbers ABCD and WXYZ (ex: 2345 and 7965). Write an algorithm using Pseudocode that decides whether ABCD is the inverse of WXYZ. (For example, if ABCD is 2356 and WXYZ is 6532 then the algorithm prints "Inverse" otherwise it will print "Not Invers")
- Python Algorithm Question (similar to celebrity Python problem). Having trouble implementing the algorithm. Here's the question: Let’s say you’re going to invite some people to a party. You’re considering n friends, but you knowthat they will only have a good time if each of them knows at least k others at the party. (Assume that if A knows B, then B automatically knows A.) Solve your problem by designing an algorithm for finding the largest possible subset of your friends where everyone knows at least k of the others, if such a subset exists. To help you get started I’ve made a graph of “my friends”: G={'Rachel':['Ross','Monica'], 'Ross':['Rachel','Monica'], 'Monica':['Rachel','Ross'], 'Jon Snow':['Daenerys','Sansa','Arya'], 'Daenerys':['Jon Snow','Sansa','Arya','Khal Drogo'], 'Sansa':['Jon Snow','Daenerys','Arya'], 'Arya':['Jon Snow','Daenerys','Sansa'], 'Khal Drogo':['Daenerys'], 'Cersei':['Jaime'], 'Jaime':['Cersei'], 'Bart':['Milhouse'], 'Milhouse':['Bart','Lisa'],…Blackout Math is a math puzzle in which you are given an incorrect arithmetic equation. The goal of the puzzle is to remove two of the digits and/or operators in the equation so that the resulting equation is correct. For example, given the equation 6 - 5 = 15 ^ 4/2 we can remove the digit 5 and the / operator from the right-hand side in order to obtain the correct equality 6 - 5 = 1 ^ 42. Both sides of the equation now equal to 1. Observe how removing an operator between two numbers (4 and 2) causes the digits of the numbers to be concatenated (42). Here is a more complicated example: 288 / 24 x 6 = 18 x 13 x 8 We can remove digits and operators from either side of the equals sign (either both from one side, or one on each side). In this case, we can remove the 2 from the number 24 on the left-hand side and the 1 from the number 13 on the right-hand side to obtain the correct equality 288 / 4 x 6 = 18 x 3 x 8 Both sides of the equation now equal to 432. Here is another puzzle for you…ID: A Name: ID: A 6. There are 32 students standing in a classroom. Two different algorithms are given for finding the average height of the students. Algorithm A Step 1: All students stand. gniwolldi odT gaihnel vd Step 2: A randomly selected student writes his or her height on a card and is seated. Step 3: A randomly selected standing student adds his or her height to the value on the card, records the new value on the card, and is seated. The previous value on the card is erased. Step 4: Repeat step 3 until no students remain standing. Step 5: The sum on the card is divided by 32. The result is given to the teacher. Algorithm B Step 1: All students stand. Step 2: Each student is given a card. Each student writes his or her height on the card. Step 3: Standing students form random pairs at the same time. Each pair adds the numbers written on their cards and writes the result on one student's card; the other student is seated. The previous value on the card is erased. Step 4: Repeat…
