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Which components in a liquid chromatography (LC) instrument are similar to the experimental set-up?
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- A) Given the following set of data, plot the chromatogram (absorbance versus volume of eluate). Vol of eluate (mL) Abs (560 nm) 0.5 0.182 1 0.108 1.5 0.042 2 0.02 2.5 0.015 3 0.083 3.5 0.052 4 0.03 4.5 0.011 0.004 5.5 6. 0.001 6.5 0.001In chromatography the concentration of a separated compound is directly related to a) stationary phase concentration b) absorbance c) wavelength d) peak areaWhat is the significance of the max of a spectrum? What are the other uses of the spectrophotometer?
- 3. The lead in a swab sample, lead standards, together with a blank were made up in 5.00 mL volumetric flasks using 0.2 % HNO3. 20 μL aliquots of these solutions were injected into the spectrophotometer and the absorbance measured at 217 nm. The following results were obtained. lead / ppb Absorbance 0 0.0591 10.00 0.0858 50.00 0.1926 100.0 0.3260 150.0 0.4594 200.0 0.5929 Swab sample 0.3700 (a) Determine the amount of lead in the swab sample in μg.Determine the slope of the linear regression line for a standard curve of concentration versus absorbance using the following data. Concentration (M) Absorbance 2.00x10-5 0.0500 5.00x10-5 0.130 1.00x10-4 0.200 2.00x10-4 0.450 5.00x10-4 1.25 7.50x10-4 1.40 Group of answer choice 5.00x10-4 1.00x10-5 1990 0.0420 0.456 0.296What is could be the calculated lambda max of this compound? 315 323 270 285
- How is light and energy used in gas chromatography- mass spectrometry (GC-MS)?The following chromatogram is obtained for a mixture of substances X and Y. Calculate the number of plates for peak X. Y 10 11 12 13 14 Tim e (min) O A. 1234 O B. 2116 OC. 1102 O D. 1936 O E. 1488 Instrument response in arbitrary unitsA solution is prepared by diluting 2.79 mL of the blue dye stock solution to 25.00 mL. The measured absorbance for the prepared solution is: Blue dye stock solution = 0.293 M Absorbance at 630 nm = 0.00265 Calibration curve y = 0.0833x A.) What is the theoretical molar concentration? B.) What is the experimental molar concentration? C.) What is the percent error?
- 10 Wavelength, 1. (nm) E (Red, µ.Mcm- ɛ(Yellow, µMr'cm¬1) Absorbance 500 0.0369 0.000549 0.405 430 0.00506 0.0167 0.474 An orange colored solution is prepared by mixing a red dye solution with a yellow dye solution and the absorbance was measured at the analytical wavelengths of 430 nm and 500 nm. The table provides the molar absorptivity for the red and yellow dye at each analytical wavelength. Calculate the concentration (in u.M) of the red and yellow dye in the mixture. [red] = [yellow] =A 10.00 g sample containing an analyte was transferred to a 250 mL volumetric flask and diluted to volume. When a 10.00 mL aliquot of the resulting solution was diluted to 25.00 mL it was found to give a signal of 0.235 (arbitrary units). A second 10.00 mL aliquot was spiked with 10.00 mL of a 1.00 ppm standard solution of the analyte and diluted to 25.00 mL. The signal for the spiked sample was found to be 0.502. Calculate the weight percent of analyte in the original sample.use the following chromatogram and table as your data. VWD: Sgrad A 284 nm Retention Time 40- -40 20 20 5 10 15 20 25 30 35 Minuteo VWD: Signal A, 284 nm Retention Area Identity Time (min) 7.867 3214697 Vitamin A 8.493 15687 19.410 140354 19.710 64346 20.803 884315 Vitamin E 21.640 36745 22.100 63054 8.403 L98 ÞI 20.803 ; 84年 81