FInd part 3 Treat h as a constant. For what values of h (if any) does the following equation have equilibria? Use a graphical argument to show which of the equilibria (if any) are stable.dydx=y5-2y-hSelect the correct choice below and, if necessary, fill in the answer box to complete your choice.OA. The equation has equilibria for(Type an inequality.)B. The equation has equilibria for all values of h.C. The equation does not have equilibria for any value of h.Separate the equation into two parts and graph each part. Indicate the direction in which y(x) moves. Choose the correct graph below.A.Ady/dx3-Y3O B.Ady/dx3-O C.-3Ady/dx3-O A. There is one stable equilibrium when, and there are no stable equilibria for other values of h.(Type your answer in inequality notation.)Y3Which of the equilibria, if any, are stable? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.OB. There are two stable equilibria when and there are no stable equilibria for other values of h.(Type your answer in inequality notation.)OC. All of the equilibria are stable for all values of h.O D. The equation does not have equilibria for any value of h.O D.Ady/dx3-AVY3Q

dy/dx = y3 – 2y – hWhich of the equilibria, if any, are stable?

Which of the equilibria, if any, are stable? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. There is one stable equilibrium when and there are no stable equilibria for other values of h. (Type your answer in inequality notation.) OB. There are two stable equilibria when and there are no stable equilibria for other values of h. (Type your answer in inequality notation.) OC. All of the equilibria are stable for all values of h. O D. The equation does not have equilibria for any value of h.