Which strings are a part of the following language? Give your answer as a set. L = {x = {0, 1}* | ³u = {0, 1}* : v = {0, 1}* : ³w = {0,1}* : (|u| = |w|) ^ (x (uvw=10110100101)} =
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- Write a program in Java programming language that reads an array of strings!The program should write all the strings from array that have at least one letter 'a'.def findOccurrences(s, ch): lst = [] for i in range(0, len(s)): if a==s[i]: lst.append(i) return lst Use the code above instead of enumerate in the code posted below. n=int(input("Number of rounds of Hangman to be played:")) for i in range(0,n): word = input("welcome!") guesses = '' turns = int(input("Enter the number of failed attempts allowed:")) def hangman(word): secrete_word = "-" * len(word) print(" the secrete word " + secrete_word) user_input = input("Guess a letter: ") if user_input in word: occurences = findOccurrences(word, user_input) for index in occurences: secrete_word = secrete_word[:index] + user_input + secrete_word[index + 1:] print(secrete_word) else: user_input = input("Sorry that letter was not found, please try again: ") def findOccurrences(s, ch): return [i for i, letter in enumerate(s) if letter == ch] *** enumerate not discussed in…Computer Science This is a codingbat problem. Please answer in Java and do not change the starter code. You have been asked to write the game of tic tac toe. In the first version of the game, we will only be comparing horizontally for a win. A win is determine by all of the elements in a row either being an X or an O. You need to return a String with the winner or TIE if there is no winner. ticTacToe(["X", "O", "O"], ["X", "O", "O"], ["X", "X", "X"]) → "X"ticTacToe(["X", "O", "X"], ["X", "X", "O"], ["O", "O", "O"]) → "O"ticTacToe(["X", "O", "X"], ["X", "X", "O"], ["O", "X", "O"]) → "TIE" public String ticTacToe(String[] top, String[] middle, String[] bottom) { }
- def sum_string(string: str) -> int:"""Given a string <string>, return the sum of this string, as computed by theformula given below: To compute the sum of a string as defined by this function, we add everyodd positioned digit, and subtract every even positioned digit. For example,if we had an input of "54321", we would add 5, subtract 4, add 3, subtract2, and add 1, bringing us to a total of 3. In other words, you would add thefirst digit, subtract the second digit, and keep alternating until you reachthe end of the string. If the string is empty, then the sum is 0. Note: since we give the input as a string, you will have to do some typeconversion in order to solve this problem. Precondition: <string> will only contain the characters 0-9."""pass " please do this on python and don't use any import functions"def strPattern(mystr): lenght = len(mystr) mystr1 = "" for i in range(lenght - 1): mystr1 = mystr1 + mystr[i].upper() + str(i + 1) if lenght == 0: return mystr1 return mystr1 + mystr[-1].upper() s = input("enter a word: ") print(strPattern(s)) s = input("enter a word: ") EOFError: EOF when reading a line how can i fix this error1. Let L = {w {a, b}* : w contains bba as a substring that starts in an odd numbered position in the string (where numbering starts at 1)}. For example, bbbbaaaab L, while bbbaaaab L. Show an NDFSM that accepts L
- java: Run length coding is a method to represent a string in a more compact manner. Each character that occurs more than 2 times in a row is represented by the character and a number following it. Two examples are: "abba" → "abba""abcccbbbba" → "abc3b4a"Write a function that calculates how many characters the encoded string is shorter than the original.def loopy_madness(string1: str, string2: str) -> str: """ Given two strings <string1> and <string2>, return a new string that contains letters from these two strings "interwoven" together, starting with the first character of <string1>. If the two strings are not of equal length, then start looping "backwards-and-forwards" in the shorter string until you come to the end of the longer string. "interwoven" (or "interweaving") means constructing a new string by taking the first letter from the first string, adding the first letter of the second string, adding the second letter of the first string, adding the second letter of the second string, and so on. "backwards-and-forwards" is a custom looping term. First the loop starts at position 1 (index 0) and goes until position n (i.e., the end). Once the loop reaches position n, it goes backwards, starting at position n - 1 and goes to position 1 (index 0). This repeats until…• get_tokens_from_equation(line): Takes one string as input that contains any combination of digits from 0-9 and the following mathematical symbols: + - x / = ^ (O The string does not have to correspond to a valid mathematical equation. For example, '4-3=0' and '4xx5=(8' could be valid inputs to this function. The function will translate the string into a list of tokens. A token is a single non-negative number (of any length) or a single mathematical symbol. Numbers should be added to the list as integers, and symbols as strings. The tokens in the list should be in the same order as the numbers/symbols appear in the string. For example, given the string '52-2=50', the function should return the list [52, '-', 50]. >>> get_tokens_from_equation('4=3') [4, '=', 3] >>> get_tokens_from_equation('6-5=15^4/2') [6, '-', 5, '=', 15, '^', 4, '/', 2] >>> get_tokens_from_equation('288/24x6=18x13x8') [288, '/', 24, 'x', 6, '=', 18, 'x', 13, 'x', 8]
- 1- Let A = [2: 0.5: 4],and B=B(2:4). What are the value of a ,and B?def is_palindrome_string(string: str) -> bool:"""Given a string <string>, return whether this string is a palindrome string.for ANY CONTINUOUS SEGMENT OF ALPHABETICAL CHARACTERS. That means that "abc;def", has two words: "abc"and "def". The separating character does not have to be whitespace, andthere could be more than one separating character between two words.A simple example: given the string "test string test", there are threewords, "test", "string", and "test". The first letters of each word cometogether to form the string "tst". And since "tst" is a palindrome, thisfunction should return True for the input "test string test".Precondition: <string> will contain at least one word.""" " please code this in python and also add this code def is_palindrome(string: str) -> bool:string = string.replace(" ", "")return string.lower() == string[::-1].lower() and use is_palindrome in the main function and also very important please don't use list or import function or…def is_palindrome_string(string: str) -> bool:"""Given a string <string>, return whether this string is a palindrome string.for ANY CONTINUOUS SEGMENT OF ALPHABETICAL CHARACTERS. That means that "abc;def", has two words: "abc"and "def". The separating character does not have to be whitespace, andthere could be more than one separating character between two words.A simple example: given the string "test string test", there are threewords, "test", "string", and "test". The first letters of each word cometogether to form the string "tst". And since "tst" is a palindrome, thisfunction should return True for the input "test string test".Precondition: <string> will contain at least one word."""