with a theoretical yield of 80% compute for the percent error of the following data Vial weight= 18.3501 vial + fluorescein weight=18.442 resorcinol = 0.1502g Phthalic anhydride= 0.1022g
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with a theoretical yield of 80% compute for the percent error of the following data
Vial weight= 18.3501
vial + fluorescein weight=18.442
resorcinol = 0.1502g
Phthalic anhydride= 0.1022g
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- Explanation is needed. Thank you! <33119 X My Course X Macmillan: X Course Mo X What is the FORMULA for the limiting reagent? Submit Answer Sections 5 X .com/static/nb/ui/evo/index.html?deploymentid=5735112480241329813180832311&elSBN=9781305862883&id=1707786042&snapshoti... Use the References to access important valdes ir needed for this question. 900 For the following reaction, 9.43 grams of carbon (graphite) are allowed to react with 28.5 grams of oxygen gas. carbon (graphite) (s) + oxygen (g) carbon dioxide (g) What is the maximum amount of carbon dioxide that can be formed? What amount of the excess reagent remains after the reaction is complete? HOMEWOR X MacBook Air MindTap - C X GI grams gramsem 119 My Course X Macmillan: X Course Mo Submit Answer X Sections 5 What is the FORMULA for the limiting reagent? References X age.com/static/nb/ui/evo/index.html?deploymentid=5735112480241329813180832311&elSBN=9781305862883&id=1707786042&snapsh What amount of the excess reagent remains after the reaction is complete? HOMEWOR Use the References to access Important values if needed for this question. For the following reaction, 20.3 grams of carbon dioxide are allowed to react with 39.6 grams of potassium hydroxide. carbon dioxide (g) + potassium hydroxide (aq) potassium carbonate (aq) + water (1) - What is the maximum amount of potassium carbonate that can be formed? MacBook Air X grams MindTap - grams ;
- What is the mass % of isopentyl acetate given the following information.Rx = 0.569Area of Isopentyl acetate peak = 197Area of Isopentyl alcohol peak = 145CATION CONFIRMATORY TEST OBSERVATION ADDED REAGENT(S) OBSERVATIONS Excess NH3 NVR KSCN NVR K4Fe(CN)6 NVR K3Fe(CN)6 NVR Na2C2O4 NVR NaOH (in evaporating dish) Litmus paper: red to blue ANION CONFIRMATORY TEST OBSERVATION ADDED REAGENT(S) OBSERVATIONS HNO3, Fe(NO3)3 Blood red aqueous layer; colorless toluene layer HNO3, KMnO4 Peach aqueous layer; colorless toluene layer (to the ppt) CH3COOH White ppt does not dissolve MgCl2 NVR 6M H2SO4, FeSO4, 18M H2SO4 NVR Select one or more: NH4+ CO32- Fe3+ SO42- Cu2+ NO3- Ca2+ I- Br- PO43- Zn2+ SCN-Chemistry pls help, I dont understand how this software wants me to enter the answer. its asking lfr the starting amount but its not taking it in the way Im putting it
- Absorbance Beer-Lambert's Law (Spectrophotometry) #2 To spectrophotometrically determine the mass percent of cobalt in an ore containing cobalt and some inert materials, solutions with known [Co"] are prepared and the absorbance of each of the solutions is measured at the wavelength of optimum absorbance. The data are used to create a calibration plot, shown below. 0.80 0.70- 8 0.60- 0.50- 0.40- 0.30 0.20- 0.10- ++- 0.015 Concentration (M) A 0.6 g sample of the ore is completely dissolved in concentrated HNO3(aq). The mixture is diluted with 2+ water to a final volume of 50.00 mL. Assume that all the cobalt in the ore sample is converted to Co'(aq). a. What is the (Co] in the solution if the absorbance of a sample of the solution is 0.74? b. Calculate the number of moles of CoT(ag) in the 50.00 mL solution. 2+ C. Calculate the mass percent of Co in the 0.630 g sample of the ore.A student is given an antacid tablet that weighed 5.6832g. The tablet was crushed and 4.3628g of the antacid was added to 200 mL of stimulated stomach acid. This was allowed to react and then filtered. It was found that 25 mL of this partially neutralized stomach acid required 8.50 mL of NAOH solution to titrations it to a methyl red endpoint. It took 21.54 mL of this NAOH solution to neutralize 25 mL of the original stomach acid. a)How much of the stomach acid had been neutralized in the 25 mL sample which was titrations? (Show work) B) how much stomach acid was neutralized by the 4.3628 g sample used? (Show work) C)How much stomach acid would have been neutralized by the original 5.6832 g tablet? (Show work)3) 3-Methylbutyramide 100 relative intensity .8888 relative abundance .88 CHINO 101 298 888 mass charge (m2) CaH₁N 60 4) n-Butylamine 100 60 CHOCHOCHS R98 8 mass charge (m/z) MW=101.15 MW-73.13
- overall aden fn tereactiorabwe! .20 what is te overall aae for tereactrobre! 200 0.00 8.00xl0 1. 0. 1000 200x1o? Trual A +BSAB On 121:4 (vv) piperidine/DMF CF,CO2H Y CH,Cl2 NH H2N. H2N H,N. NH NH2 NH3 NH2 + II II IV Consider the reaction scheme given above. What are products 'X' and 'Y'? O X = II; Y = IV O X = IV; Y = || O X = II; Y = II O X= 1; Y = IIMacmillan Learning The selenium content in soil can be determined fluorometrically upon conversion of the selenium to the fluorescent product shown, followed by extraction in cyclohexane. Emission from the fluorescent product is observed at 518 nm. a The selenium content in a 0.147 g soil sample was converted to the fluorescent product and extracted in 50.0 mL of cyclohexane. The method of standard additions was used to determine the selenium content in the soil sample. Initially, 3.00 mL of the cyclohexane solution were placed in a cuvette for fluorescence determination. Several small additions of a 2.66 µg Se/mL standard solution containing the fluorescent product were added to the 3.00 mL solution in the cuvette. The fluorescence was measured at 518 nm. The results are shown in the table. Total added Se standard volume (µl) 0.00 20.0 40.0 60.0 80.0 Se wt% = 50625 Fluorescence intensity (arbitrary units) Determine the weight percent (wt%) of selenium in the soil sample and find the…