Write a function label_squarer that mutatesa Tree with numerical labels so that eachlabel is squared.def label_squarer(t):"""Mutates a Tree t by squaring all its>>> t = Tree(1, [Tree(3, [Tree(5)]), Tr>>> label_squarer(t)>>> tTree(1, [Tree(9, [Tree(25)]), Tree(49).IL I| |"*** YOUR CODE HERE ***"

Answered: Write a function label_squarer that…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write the following function: The function gets a root of a Binary Tree of ints, and a function f. it applies f to the data of each node in the tree. // applies f to each node of the tree under root void map(BTnode_t* root, int (*f)(int)); struct BTnode { int value; struct BTnode*left; struct BTnode*right; struct BTnode*parent; }; typedef struct BTnode BTnode_t; BTNODE.C: BTnode_t* create_node(int val) { BTnode_t* newNode = (BTnode_t*) malloc(sizeof(BTnode_t)); newNode->value = val; newNode->left = NULL; newNode->right = NULL; newNode->parent = NULL; returnnewNode; } void set_left_child(BTnode_t* parent, BTnode_t* left_child) { if (parent) parent->left = left_child; if (left_child) left_child->parent = parent; } void set_right_child(BTnode_t* parent, BTnode_t* right_child) { if (parent) parent->right = right_child; if (right_child) right_child->parent = parent; } void print_pre_order(BTnode_t* root) { if (root == NULL) return; printf("%d ",…
A BST is constructed in the usual way using the node definition below. Write a function int child2( bst node t *curr) that returns the number of nodes that have 2 children. typedef struct BST NODE T {int data;struct BST NODE T *left, *right; } bst node t; int child2( bst node t *curr){ }
Make an array of linked list for the following C code: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 = poly1->next;} // If power of…
In C++ Please Write a struct Student that has member variables: (string) first name, (int) age and (double) fee. Implement the Splay tree whose each node has data component an instance of the struct Student. Comparison of the nodes must be made with respect to age. Write the following functions along with necessary functions to: (i) search elements in the tree; (ii) insert nodes in the tree; (iii) print the tree in pre-order traversal fashion; (iv) delete a node from the tree; Implement the following (you can hardcode the inputs): (i) insert seven elements in the tree: (Kabeer, 19, 35.17), (John, 21, 31.65), (Paul, 25, 33.43), (Kaur, 18, 34.93), (Patel, 23, 36.37), (Alexander, 22, 33.78), (Ramesh, 27, 34.46); (ii) print the tree in pre-order fashion; (iii) delete an element from the tree (John, 21, 31.65); (iv) search an element (Alexander, 22, 33.78) in the tree; (v) print the tree in pre-order traversal fashion;
Write a insertion code of Red Black Tree in C++. Use this follwing Structure of Node (you cannot change it): struct Node{int data;Node*leftChild;Node*rightChild;char colour;};
Suppose we have a tree type and a variable t defined as follows: datatype tree = Node of tree * int * tree| Leafval t = Node(Node(Leaf, 1, Leaf), 2, Node(Leaf, 3, Leaf))Note that t is a tree of the following form:Node 2/ \Node 1 Node 3/ \ / \L L L L Write a function maxTree that finds the maximum values within a tree.For example, maxTree t returns 3. Note that this is NOT a searchtree. This function assumes that the input tree is not a Leaf. IN SML SHOW OUTPUT WORKING
4. Complete the fuction definition given below that takes the root node of a tree as a parameter and returns the count of nodes. int count_nodes(Node *root){ // complete the function }
Given the following struct that represents a binary tree: struct Node { int key: Node "parent; Node "left; Node "right; Nodelint k) : key(k), parent(nullptr), left(nullptr), right(nullptr) (I: 1: Write a recursive function that prints out the nodes in a tree stored using the above structure in order to cout. The function prints the depth (root depth is at 0) and key of that node separated by a colon (Example "O: 10\n" for root with key 10). Your function CAN NOT create any local variables and can only use what is passed to the function. Use the below function signature (NOTE: this is not a class method). void inorderAndDepth(Node "node, int depth)
please convert to C languange #include<bits/stdc++.h>using namespace std; class tree{ //tree node public: int data; tree *left; tree *right;}; bool hasRootToLeafSum(tree *root, int s){ bool path=false; //declare boolean variable path //base condition checking if(root==NULL && s==0) return true; s-=root->data; //subtract current root value //checking whether leaf node reached and remaining sum =0 if(s==0 && root->left==NULL && root->right==NULL) return true; //recursively done for both subtrees if(root->left){//for left subtree path=path||hasRootToLeafSum(root->left, s); } if(root->right){//for right subtree path=path||hasRootToLeafSum(root->right, s); } return path;} tree* newnode(int data){ //creating new nodes tree* node = (tree*)malloc(sizeof(tree)); node->data = data; node->left = NULL; node->right = NULL;…
Modify the given code to accept float instead of int as a coefficient in C LANGUAGE: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 =…
C++ DATA STRUCTURES Implement the TNode and Tree classes. The TNode class will include a data item name of type string,which will represent a person’s name. Yes, you got it right, we are going to implement a family tree!Please note that this is not a Binary Tree. Write the methods for inserting nodes into the tree,searching for a node in the tree, and performing pre-order and post-order traversals.The insert method should take two strings as input. The second string will be added as a child node tothe parent node represented by the first string. Hint: The TNode class will need to have two TNode pointers in addition to the name data member:TNode *sibling will point to the next sibling of this node, and TNode *child will represent the first child ofthis node. You see two linked lists here??? Yes! You’ll need to use the linked lists
Write a deletion code of Red Black Tree which delete a node in C++. Use this follwing Structure of Node: struct Node{int data;Node*leftChild;Node*rightChild;char colour;};

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Write a function label_squarer that mutates a Tree with numerical labels so that each label is squared. def label_squarer(t): "" "Mutates a Tree t by squaring all its II || >>> t = Tree(1, [Tree(3, [Tree(5)]), Tr >>> label_squarer(t) >>> t