Write the output that will be obtained when this traverse() method is called with the root of the tree given below.
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Write the output that will be obtained when this traverse() method is called with the root of the tree given below.
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- class Node { int key; Node l, r; public Node(int item) { key = item; l = r = null; }} class Main{ Node root; Main() { root = null; } void Postorder(Node node) { if (node == null) return; Postorder(node.l); Postorder(node.r); System.out.print(node.key + " "); } void Inorder(Node node) { if (node == null) return; Inorder(node.l); System.out.print(node.key + " "); Inorder(node.r); } void Preorder(Node node) { if (node == null) return; System.out.print(node.key + " "); Preorder(node.l); Preorder(node.r); } void Postorder() { Postorder(root); } void Inorder() { Inorder(root); } void Preorder() { Preorder(root); } public static void main(String[] args) { Main tree = new Main(); tree.root = new Node(27); tree.root.l =…c++ programming Complete all these 2 methods for the node Node methods •int get_depth(): Returns the depth of the node. •int get_height(): Returns the height of the node. Initial code to be completed:struct node { node* parent; node* right; node* left; int element; int get_depth() { return 0; } int get_height() { return 0; }};dict1 = {(1,1,1):"red", (2,1,-1):"green", (0,-1,1):"red", (0,0,-2):"blue"}In this case, there are 2 red points, and their centroid is at ( (1+0)/2, (1-1)/2, (1+1)/2 ) = (0.5, 0, 1)Considering that in this example there is only one green and one blue point, they are representing the respective color's centroid. Hence, your function should return the following dictionary:{"red":(0.5,0.0,1.0), "green":(2.0,1.0,-1.0), "blue":(0.0,0.0,-2.0)}
- Multiple choice in data structures int doo(node<int>*root){ if(root !=0 ) { if(root->left==0 && root->right==0) return root->data; int L=doo(root->left); int R=doo(root->right); if(L>R) return R; else return L;} } this code used for a. the maximum item in the leaves of a binary tree b. find the minimum item in the leaves of a binary tree c. find the sum of leaves items in a binary tree d. find the minimum item in a binary treePLEASE HELP ME! ? Maximize and use alternative method to this code! package com.btech.pf101; import java.io.bufferedreader; import java.io.inputstreamreader; import java.util.calendar; import java.util.date; public class pawnshopcode { private static final bufferedreader br = new bufferedreader(new inputstreamreader(system.in)); private static string name; private static int age; private static string address; private static string contactno; private static int itemtype; private static string itemtypename; private static final int itemtype_gagdet = 1; private static final int itemtype_jewelry = 2; private static final int itemtype_musicinstrument = 3; private static final int itemtype_homeequipment = 4; private static final int itemtype_landtitle = 5; private static string itemdescription; private static int periodtype; private static string periodtypename; private static final int periodtype_days = 1; private…In C, using malloc to allocate memory for a linked list uses which memory allocation scheme? Heap allocation Static allocation
- Parking (car Cars[], car Park[], int Area) { Car Cr, int CrNb; CrNb <-- 0; Park <-- { }; Cr <-- Select (Cars) I/ Cr = / if the Cars = {} while (Feasible (Cr)) do { Remove (Cr, Cars); Add (Cr, Park); CrNb <-- CrNb +1; Cr <-- Select (Cars) } if exist-Solution (Park) Then Success else return Error } Trace the above Greedy algorithm with the following data: Area = 1000, Cars [100, 50, 90, 70. 200, 300, 400, 80, 200] the cost for each parked car is 3JD. The objective function is: %3D k Max (ΣCis 1000) K |=1Trace through the following program and show the output. Show your work for partial credit. public class Employee { private static int empID = 1111l; private String name , position; double salary; public Employee(String name) { empID ++; this.name 3 пате; } public Employee(Employee obj) { empID = obj.empĪD; пате %3D оbj.naте; position = obj.position; %3D public void empPosition(String empPosition) {position = empPosition;} public void empSalary(double empSalary) { salary = empSalary;} public String toString() { return name + " "+empID + " "+ position +" $"+salary; public void setName(String empName){ name = empName;} public static void main(String args[]) { Employee empOne = new Employee("James Smith"), empTwo; %3D empOne.empPosition("Senior Software Engineer"); етрOпе.етpSalary(1000); System.out.println(empOne); еmpTwo empTwo.empPosition("CEO"); System.out.println(empOne); System.out.println(empTwo); %3D етpОпе empOne ;Hef sharks_minnows (minnows, sharks): shark_count = 0 minnow_count = len (minnows) for i in range(minnow_count): curr_shark_height = minnows [i] if curr_shark_height is not None: minnows [i] = None for j in range (i + 1, minnow_count): if minnows [j] == curr_shark_height: minnows [j] = None curr_shark_height -- 1 shark_count += 1 return shark_count <= sharks The provided code is imperfect, in that it sometimes returns True when it should return False, and sometimes returns False when it should return True. (a) Provide an example of a function call where the provided code will correctly return True (i.e. a True Positive) (b) Provide an example of a function call where the provided code will correctly return False (i.e. a True Negative) (c) Provide an example of a function call where the provided code will incorrectly return True (i.e. a False Positive) (d) Provide an example of a function call where the provided code will incorrectly return False (i.e. a False Negative)
- Computer Science A tool is attached to link 3 of the manipulator. This tool is described by TTW, the tool frame relative to the wrist frame. Also, a user has described his work area, the station frame relative to the base of the robot, as TSB. Write the subroutine Procedure SOLVE(VAR trels: frame; VAR current, near, far: vec3; VAR sol: boolean); where “trels” is the {T} frame specified relative to the {S} frame. Other parameters are exactly as in the INVKIN subroutine. The definitions of {T} and {S} should be globally defined variables or constants. SOLVE should use calls to TMULT, TINVERT, and INVKINC++ PROGRAMMING Please implement these 2 methods for the node where: •int get_depth(): Returns the depth of the node. •int get_height(): Returns the height of the node. Initial code to be completed: Note: Do not add new member variables for the depth and height. struct node { node* parent; node* right; node* left; int element; int get_depth() { return 0; } int get_height() { return 0; }};mkfifo("mypipe"); if (!fork()) { fp = popen("echo 37 > mypipe", "w"); %D status = pclose(fp); } else { printf("14"); sleep(1); fp = popen("cat mypipe", "r"); fgets(buffer, buffer_size, fp); printf("%s", buffer); status = pclose(fp); %3D } Consider the above code fragment, what's the output to stdout?