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You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with approximately 200 mL of water. You now need to determine its precise concentration and you have performed five titration trials to standardize your solution. Here are the results of your trials: trial # mass of potassium biphthalate (mg) volume of NaOH solution (mL) 12.30 mL 1 180 mg 15.20 mL 2 180 mg 12.20 mL 3 180 mg 13.90 mL 4 180 mg 12.50 mL 5 180 mg You now have to calculate the average molar concentration of your NaOH solution and you want it to be as precise as possible. How are you going to do it? I will only use trials 1 and 3 I will use all the trials for my calculations I will discard trial 4 I will discard trials 2 and 4

You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with approximately 200 mL of water. You now need to determine its precise concentration and you have performed five titration trials to standardize your solution. Here are the results of your trials: trial # mass of potassium biphthalate (mg) volume of NaOH solution (mL) 12.30 mL 1 180 mg 15.20 mL 2 180 mg 12.20 mL 3 180 mg 13.90 mL 4 180 mg 12.50 mL 5 180 mg You now have to calculate the average molar concentration of your NaOH solution and you want it to be as precise as possible. How are you going to do it? I will only use trials 1 and 3 I will use all the trials for my calculations I will discard trial 4 I will discard trials 2 and 4

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with approximately 200 mL of water. You now need to determine its precise concentration and you have performed five titration trials to standardize your solution. Here are the results of your trials: trial # mass of potassium biphthalate (mg) volume of NaOH solution (mL) 12.30 mL 1 180 mg 15.20 mL 2 180 mg 12.20 mL 3 180 mg 13.90 mL 4 180 mg 12.50 mL 5 180 mg You now have to calculate the average molar concentration of your NaOH solution and you want it to be as precise as possible. How are you going to do it? I will only use trials 1 and 3 I will use all the trials for my calculations I will discard trial 4 I will discard trials 2 and 4
Transcribed Image Text:You have prepared a solution of NaOH by diluting a stock 1.5 M NaOH solution with approximately 200 mL of water. You now need to determine its precise concentration and you have performed five titration trials to standardize your solution. Here are the results of your trials: trial # mass of potassium biphthalate (mg) volume of NaOH solution (mL) 12.30 mL 1 180 mg 15.20 mL 2 180 mg 12.20 mL 3 180 mg 13.90 mL 4 180 mg 12.50 mL 5 180 mg You now have to calculate the average molar concentration of your NaOH solution and you want it to be as precise as possible. How are you going to do it? I will only use trials 1 and 3 I will use all the trials for my calculations I will discard trial 4 I will discard trials 2 and 4
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