you perform a cross of two heterozygous, red-eyed flies. They have 100 offspring. How many of these offspring do you predict will have red eyes? Show your work using a Punnett square. [Use letters R and r to designate the alleles]
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you perform a cross of two heterozygous, red-eyed flies. They have 100 offspring. How many of these offspring do you predict will have red eyes? Show your work using a Punnett square. [Use letters R and r to designate the alleles]
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- How would I figure this out using a punnett square? Next, you perform a cross of two heterozygous, red-eyed flies. They have 100 offspring. How many of these offspring do you predict will have red eyes? Show your work using a Punnett square. [Use letters R and r to designate the alleles].type P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONSThe table below shows the progeny of a test cross of a heterozygote (JjBbRr). Each row shows the number of progeny that inherited each combination of alleles from the heterozygous parent. You've already determined the gene order (B is in the middle) and labeled each type of progeny. Using this information, what is the recombination frequency between J and B? Alleles: Type: Count: J B R Parental 132 j b r Parental 135 J b R DCO 15 j B r DCO 11 J b r SCO (J-B) 59 j B R SCO (J-B) 55 J B r SCO (B-R) 38 j b R SCO (B-R) 40 Group of answer choices 0.214 0.235 0.289 the correct answer is not available. 0.503 0.14
- Fruit fly body color is wild type (meaning normal) Gray = B+ and black = b Fruit fly wing type is wild type normal wings = vg+ and vg = vestigial A fly which was heterozygous for both traits was crossed with a fly that was recessive for both traits. Write the genotype and phenotype that would be expected from this cross. Write the genotype and phenotype percentages that would be expected from this cross.If a red flower is crossed with a white flower to produce an offspring with red and white petals, what is the relationship between the alleles for flower color? show your solution using punett squareProduce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no letters, no spaces. There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the…
- If a red flower was mated with white flower, they produced a pink flower, what could you say about the relationship between the alleles of the red and white flowers? show your solution using punnet squareA friend tells you that her biological father has an inherited disorder determined by a dominant allele but neither your friend nor her three siblings are affected. Is this possible? If not, why not? If so, explain how it is possible. For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Arial 14px A V x² X, ABC 田 田 | 国田用田 Ť {;} III !!! +)pt pt PT PPTt purple tall PpTt purple tall Pt Pptt purple white Pptt purple white Using any two plants resulting from your test cross (even two of the same genotypes if you would prefer), perform a second cross. Provide a Punnett square demonstrating this dihybrid cross.What are the ratios for each genotype in the resulting offspring? What are the ratios for each phenotype? Your answer should clearly indicate the genotype and phenotype each portion of the ratio is referring to
- Produce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no letters, no spaces. There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the…SEATWORK Symbols (for pea plant traits): • T: Tall t: short Analyze the following problems. Determine the possible genotypes, genotypic ratio, phenotypes, and phenotypic ratio from the genetic cross. Show your solution through a Punnett square. Use the symbols provided. • R: Round seeds r: wrinkled seeds • Y: Yellow seeds y: green seeds • P: Purple flower p: white flower 1) Cross a homozygous dominant tall and homozygous round seed pea plant with a heterozygous tall and heterozygous round seed pea plant. 2) Cross a pea plant that is heterozygous for purple flowers and homozygous dominant for yellow seeds with a pea plant that is heterozygous for purple flowers and homozygous recessive for green seeds. 3) Cross a pea plant that is short and has green seeds with a pea plant that is heterozygous tall and has heterozygous yellow seeds.The result of a test cross of a yeast cell that is heterozygous for three genes are summarized in the table (below), which shows the number of offspring that inherited each combination of alleles from the heterozygous parent. Use the data collected to make a genetic map of the three genes L, Q, and D. • D-Q: o D-L: | o Q-L: | - L L I L L cM CM Alleles CM Ơ Ơ o Q o d D D d d d # 104 27 78 Report your results by entering the genetic distance between each pair of genes in the blanks below. Round to the nearest 0.1 cm. 64 28 62 106 81