You want to construct a photocell that works withvisible light. Three materials are readily available:aluminum (Wo= 4.28 eV), lead(Wo = 4.25 eV), and cesium (W0 = 2.14 eV).Part AWhich material(s) would be suitable?aluminumleadcesium

Introduction:The maximum photon energy for visible light is 3.26 eV (Violet) So, only materials with…

Answered: You want to construct a photocell that…

Modern Physics

3rd Edition

ISBN:9781111794378

Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Chapter3: The Quantum Theroy Of Light

Section: Chapter Questions

Problem 42P

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The work function for potassium is 2.26 eV. What is the cutoff frequency when this metal is used as photoelectrode? What is the stopping potential when for the emitted electrons when this photo electrode is exposed to radiation of frequency 1200 THz?
A laser with a power output of 2.00 mW at a 400-nm wavelength is used to project a beam of light onto a calcium photoelectrode. (a) How many photoelectrons leave the calcium surface per second? (b) What power is carried away by ejected photoelectrons, given that the work function of calcium is 2.31 eV? (c) Calculate the photocurrent. (d) If the photoelectrode suddenly becomes electrically insulated and the setup of two electrodes in the circuit suddenly starts to act like a 2.00-pF capacitor, how long will current flow before the capacitor voltage stops it?
The work function of each Lithium and Beryllium and Mercury is 2.3eV,3.9eV,4.5eV. If light with λ=400nm drop on thes metals. A) the Photoelectric effect will appear in which metal? B) the maximum point of kinetic energy of photonic electrons in each state.
Barium has a work function of 2.48 eV. 1. a) What is the maximum kinetic energy of electrons if the metal is illuminated by UV light of wavelength 365 nm? 2. b) What is their speed?
You want to construct a photocell that works with a visible light. Three materials are readily available: aluminum (W0 = 4.28 eV), lead (W0 = 4.25 eV), and cesium (W0 = 2.14 eV). Which material(s) would be suitable?
b) Two light sources are used in a photoelectric experiment to determine the work function for a particular metal surface. When green light from a mercury lamp (2 = 546.1 nm) is used, a stopping potential of 0.376 V reduces the photocurrent to zero. Based on this measurement, %3D i. Calculate the work function for this metal. ii. If the yellow light from a helium discharge tube (2 = 587.5 nm) is used, find the %3D new stopping potential.
A light source is used in a photoelectric experiment. The metal copper is illuminated, if a stopping potential of 1.03 V is required, what is the energy of the light shining on the metal in eV? Answer to FIVE decimal places. Do NOT enter units. Use and carry ALL your digits of your calculator. Metal #Metal o (eV) 1 Ag 4.73 Al 4.08 Cu 4.70 4 Fe 4.50 Na 2.46 6. Pb 4.14 Pt 6.35 Zn 4.31 our Answer:
The photoelectric effect in a cosmic context. Ultraviolet radiation striking dust grains composed of the moon’s dominant rock type, feldspar (with work function 4.5 eV), leaves them with a small electric charge. Smaller grains levitate due to the resulting electrostatic repulsion, giving the surface a diffuse dust halo. 200 nm ultraviolet strikes a dust grain and ejects an electron.What is the electron’s kinetic energy?A. 1.7 eV B. 4.5 eVC. 6.2 eV D. 10.7 eV
QUESTION 7 A metal having a work function of 2.8 eV is illuminated with monochromatic light whose photon energy is 3.9 eV. What is the threshold frequency for photoelectron production? (h-6.626 x 10-34 J-s-4.141 x 10-15, eV s, 1 eV 1.60 x 10-19 J CA 8.5 x 10¹4 Hz OB. OC 6.8 x 10¹4 Hz 7.6 × 10¹4 Hz 2.7 x 10¹4 Hz
▼ In a photoelectric-effect experiment, the stopping potential is 1.37 V if the light used to illuminate the cathode has wavelength 475 nm. Find the work function (in eV) of the cathode material. Express your answer in electron volts. φ= Submit Part F 15. ΑΣΦ Vo = Request Answer μA Find the stopping potential if the wavelength is decreased to 425 nm. Express your answer with the appropriate units. Value Submit Request Answer P Units ? 599 eV ?
You want to construct a photocell that works with visible light. Three materials are readily available: aluminum 1W0 = 4.08 eV2, lead 1W0 = 4.25 eV2, and cesium 1W0 = 2.14 eV2. Which material(s) would be suitable?
A gold cathode (work function = 5.1 eV) is illuminated with light of wavelength 250 nm. It is found that the photoelectron current is zero when AV = 0 V. Would the current change if: a. The intensity is doubled? b. The anode-cathode potential difference is increased to AV= 5.5 V? c. The cathode is changed to aluminum (work function = 4.3 eV)?

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You want to construct a photocell that works with visible light. Three materials are readily available: aluminum (Wo= 4.28 eV), lead (Wo = 4.25 eV), and cesium (W0 = 2.14 eV). Part A Which material(s) would be suitable? aluminum lead cesium