Electrical Engineering: Principles & Applications (7th Edition)
7th Edition
ISBN: 9780134484143
Author: Allan R. Hambley
Publisher: PEARSON
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Chapter 14, Problem 14.9P
A long copper pipe carries a dc current. Is there a magnetic field inside the pipe due to the current? Outside? Justify your answers.
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An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current
I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the
iron is a consistent 0.8 cm?, and the mean length of the flux path is 0.15 m.
a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance
in each part of the circuit.
b) State's Ohm's Law for magnetic circuit.
c) By neglecting the effect of fringing, calculate the reluctance of the circuit.
d) Find the flux within the core.
N = 6000
Iron circuit (4, = 800 for iron).
Figure 1
A biped magnetic core (core) is shown in the figure. The coil on the left leg of this core (N1)
has 400 turns and. the right (N2) winding has 300 turns. Coils are wound in the directions
shown in the figure. The core depth is (15 cm) and the dimensions of the core are as shown
in the figure
How much flux (@=?) is produced by coil currents İ1 = 5 A and 12 = 10 A
Assume ur = 1000 and constant
Please I want the answer step by step.
50 cm
*
15 cm
50 cm
15 cm
15 cm-
400 turns
N₁
300 turns
N₂
15 cm-
½
Core depth = 15 cm
An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current
I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the
iron is a consistent 0.8 cm2, and the mean length of the flux path is 0.15 m.
a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance
in each part of the circuit.
b) State's Ohm's Law for magnetic circuit.
c) By neglecting the effect of fringing, calculate the reluctance of the circuit.
d) Find the flux within the core.
N = 6000
Iron circuit (4, = 800 for iron).
Chapter 14 Solutions
Electrical Engineering: Principles & Applications (7th Edition)
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- Q5. In the magnetic circuit of Figure-2, the relative permeability of the ferromagnetic material is 1200. Neglect magnetic leakage and fringing. All dimensions are in centimeters, and the magnetic material has a square cross-sectional area. Determine the air gap flux, the air gap flux density, and the magnetic field intensity in the air gap. 10 A N₁ 500 turns 2 50 50 2 0.5 50 Figure-2: Magnetic circuit 2 N₂ 500 turnsarrow_forward2. A current of I = 3 [A] flows over the N = 200 winding wire as given in the figure below. The cross-sectional area of the core is S = 10-3 [m²] and its relative magnetic permeability is given as μ = 5000. Calculate each magnetic flux. -0.2 (m)- 2 (mm) -0.2 (m) 0.24 (m)arrow_forward1. What is the relationship between voltage and current when there is saturation in the magnetic circuit? 2. When there is no saturation in the magnetic circuit, what is the relationship between voltage and current? 3. Briefly explain what caused the saturation in the magnetic circuit. 4. What happens to alternating current, alternating current, and alternating magnetic flux in a magnetic circuit when frequency increases? 5. When a magnetic circuit is saturated, explain two solutions that can be used so that the magnetic circuit is no longer saturated.arrow_forward
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- For the magnetic circuit shown in the figure, the iron core with N = 500 turns -Magnetic permeability is 200. its average length is 10 cm -The diameter of the cross-sectional area is 1 cm. Find the current that must pass through the winding to produce 0.5 mWb of flux in a 1mm air-gap magnetic circuit?arrow_forward7) A square magnetic core has a mean path length of 55 cm and a cross- sectional area of 150 cm². A 200-turn coil of wire carrying a current of 0.316 A is wrapped around one leg of the core. What is the magnetomotive force created by the system?arrow_forwardQUESTION 1 A ferromagnetic core is shown in Figure 1. The depth of the core (in to page) is 15cm, and the other dimensions are shown in the figure. There is a 150-turn coil wrapped around the left side of the core with input current is 2 Ā. a) Draw and label a magnetic circuit of ferromagnetic core below b) Assuming relative permeability, pr of 2400,calculate: i. Total reluctance ii. Magnetomotive force of the circuit Total flux of the circuit ii. 15cm 20cm 15cm 15сm N= 150 20cm 15cm 15cm 20cm 15cm Figure 1: Ferromagnetic Corearrow_forward
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