The magnetic moment of the Earth is approximately 8.00 x 1022 A ⋅ m2. Imagine that the planetary magnetic field were caused by the complete magnetization of a huge iron deposit with density 7 900 kg/m3 and approximately 8.50 x 1028 iron atoms/m3. (a) How many unpaired electrons, each with a magnetic moment of 9.27 x 10-24 A ⋅ m2, would participate? (b) At two unpaired electrons per iron atom, how many kilograms of iron would be present in the deposit?

a) The required number of unpaired electron is,

Answered: The magnetic moment of the Earth is…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 59P

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The magnetic moment of the Earth is approximately 8.00 x 10²² A ⋅ m². Imagine that the planetary magnetic field were caused by the complete magnetization of a huge iron deposit with density 7 900 kg/m³ and approximately 8.50 x 10²⁸ iron atoms/m³. (a) How many unpaired electrons, each with a magnetic moment of 9.27 x 10^-24 A ⋅ m², would participate? (b) At two unpaired electrons per iron atom, how many kilograms of iron would be present in the deposit?

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