1/v (sec/μmol) Enzymes A and B catalyze different reactions but use the same reactant molecule as a substrate. The graph below presents the double-reciprocal plots observed when enzyme A and enzyme B are mixed together in a single test tube containing molecule X. X 12° 1> 0.45 0.40 Y 0.35 0.30 Z 0.25 0.20 0.15 0.10 2.05 0.00 -1.20 -1.00 -0.80 -0.60 -0.40 -0.20 0.00 0.20 0.40 0.60 0.80 1.00 1.20 1/[X] (1/μM) A-B What are the Vmax and the Km values for each enzyme under these conditions? A Vmax = 5.9 μmol sec KM = 1.00 μΜ B Vmax = 10. μmol sec KM = 3.0 μΜ
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- The concentration of hydrolyzed nitrocefin at each time point for an experiment is given below. Time (min) Concentration (μM) 0.5 6.01 1 11.78 1.5 17.6 2 23.51 2.5 29.58 3 35.31 3.5 39.73 4 44.5 4.5 48.18 5 50.05 5.5 52.72 6 54.01 6.5 55.06 7 55.65 7.5 56.39 8 56.74 8.5 57.49 9 58.03 9.5 58.61 10 58.69 Make a graph that plots the concentration of hydrolyzed nitrocefin (in μM) against time (in seconds) using Excel, R, SPSS or other computable software. Where appropriate, include a trendline that shows the linear range on your graph. Include the equations for the trendlines and the R2 value on the graph. Your graph should also include a title and appropriate titles for the x- and y-axes, with units included where appropriate. To determine the initial velocity of a possible insert in this experiment, you must determine what the linear range is in these data (see note below). Based on your graph, which time points represent a suitable linear…This is my data collected from a Succinate Dehyrogenase Enzyme Assay - I am asked to plot a Concentration vs Time while plotting the Resuspended and Supernatant Reaction; how can this be completed? Test Tube Concentration (uM) Absorbance @ 600nm #1 0 0.00 #2 5 0.090 #3 10 0.187 #4 20 0.368 #5 40 0.715 #6 60 1.075 Table 3. Succinate Dehydrogenase Assay @ 600 nm Time point (min): Resuspended Pellet Reaction Absorbance Supernatant Reaction Absorbance Enzyme Reaction Control Absorbance 0 43.2 44.2 46.1 3 43.3 44.8 6 43.0 44.9 9 42.6 45.2 12 43.5 45.6 15 44.0 45.7 18 43.8 45.9 21 44.0 46.4 24 44.1 46.5 27 43.9 46.7 30 43.7 46.9 43.6You have an order for 1 gram of Cefazolin in D5W 100 ml. You have added 5 ml of sterile water to the 1 gram vial to reconstitute powder. However the recommended manufacturer’s diluent amount is 10 ml of sterile water for a final concentration of 100 mg/ml. How would reconstituting the vial with 5 mls affect the concentration and the final calculated dose. Please answer with explanation ASAP. I will really upvote. Thanks
- Please note the following Lineweaver-Burk plot for the enzyme Virbraniumase reacting with a substrate: -0.4 . 1/V 5 4 3 2 -0.2 0 0.2 y = 5.2781x + 1.3338 R² = 0.9967 0.4 0.6 0.8 1/[S] 1 Based on the information provided, what is the Vmax for this reaction?The phenol concentration of wastewater was determined from three (3) parallel determinations, giving a mean of 0.513 μg L-1 and a standard deviation of 0.05 μg L-1. Decide at a risk level of 5% (or a confidence level of 95%) whether a reference value of 0.520 μg L-1 is statistically different.Nicotiana tabacum cells are cultured to produce a polysaccharide gum. The reactor used is a stirred-tank reactor with an initial volume of 100 L. The maximum specific rate of growth of the culture is 0.18 d-1 and the yield coefficient of substrate in biomass is 0.5 gX/gS. The concentration of the limiting substrate in the medium is 3% (m/v). The reactor is inoculated with 1.5 g/L of cells and operated in batch until the substrate is exhausted, when the medium is fed with a constant flow rate of 8 L/d. The fed batch occurs in a quasi-steady state condition.a) Estimate the time of the batch step and the concentration of cells reached in this phase, considering exponential cell growth.b) The fed batch phase is carried out for a period of 40 days. What is the final concentration of cells in the reactor?c) The bioreactor is available for the process for 275 days a year, with an interval of 24 hours between each cultivation. What is the most advantageous operating mode for the process…
- You are given as following : 20 µl pure LDH on ice, 2.0ml of 6mM NAD+, 2.0ml of 150mM lactate, and 0.14M CAPS buffer. LDH reaction cocktail has final concentration of 1mM NAD+ and 25mM lactate in 0.14M CAPS buffer. LDH activityis measured by mixing 10 µl of LDH sample and 990 µl LDH reaction cocktail before getting ∆A340/min reading on spectrometer. (a). Describe in detail how you would prepare for your LDH reaction cocktail including how to make dilutions.Match the number in the image with the correct name for the lab supply 1 2 ♡ AGEN QIAGEN QIAGEN QIAC RIVCEM БИЗӘДІС RNeasy Mini Kit (50) Cat. No. 74104 Store at room temperature (15-25°C) WEZAIO QIAGEN 2 GDIVERM QIAGL K (20) QIAGL умени DAIO QIAG GAGEN GIVCEN QIAGEN QIAGEN ИЗОМО QIAGEN NEA QIAGEN QIAGEN N QIAGEN QIAGE Buffer W AGEN Lysis buffer 45 m Buffer RPE Wash buffer 11 ml concentrate to ustan 5 m Butter R U 3 clear collection tube centrifuge tube pink column (with filter) PhaseLock tube pink column (with filter) inside a clear collection tube <Calculate the amount of phycocyanin in Sample 1 in mg where A620=0.204 and A650=0.061, taking into account the dilution factor as per question 6, and the total volume of extract as per question 4. Note your answer to 2 decimal places Sample 1 Total Extract Volume (ml) is 45 Dilution factor is 100 A280 is 1.07 A620 is 0.221 A650 is 00.97 Specific Absorbance Ratio (SAR) A620/A280 is 0.206
- A patient received a single 245.97 mg IV bolus dose of an antibiotic and the plasma drug concentration was determined as 13.62 mg/L and 5.94 mg/L at 2.04 hours and 11.52 hours following the drug administration, respectively. On a separate occasion, a single 427.73 mg oral dose of the same antibiotic was administered to the same patient and the plasma drug concentration was determined as 0, 5.01, 5.77, 3.43, 1.1 mg/L at 0, 3.15, 7.69, 14.39, and 27.5 hours following the drug administration. Please calculate the bioavailability of this drug without utilizing any data fitting program.The accompanying figure is from an electrophoresis experiment using SDS–PAGE. The left lane has the following standards: bovine serum albumin (MW 66,000), ovalbumin (MW45,000), glyceraldehyde 3-phosphate dehydrogenase (MW 36,000),carbonic anhydrase (MW 24,000), and trypsinogen (MW 20,000).The right lane is an unknown. Calculate the MW of the unknown.A 10-L stirred tank is used to cultivate mouse myeloma cells. Dry air is sparged from the bottom at 1.0 L/min to supply oxygen to the system. The gas composition at the outler is 16% oxygen, 3.5% CO2, 6.5% water vapor, and balanced nitrogen. The ambient pressure and temperature are 1 atm and 37 °C, respectively. The dissolved oxygen in the reactor is controlled at 20% of saturation with ambient air. What is the respiratory quotinent (RQ) (i.e., mole CO2 produced/mol O2 consumed)? Assume that the mole fraction of CO2 in the ambient air is negligible. The universal gas constant R = 0.082 L*atm/mol*K