2. Find i(t) 100 V (+ 20 Ω 502 www t=0▼ 502 ww 1 H m 112 F
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- 9 62 802 5 mH 一 80V 156 1oov o=t エ has been n positien it moves to position The Switeh n the civauit in for a log time. At +=0 b. Find reltl for t70.Determine the value of 'w' in the figure such that the peak value of i(t) is 0.25 A. Use the VR2 + X², identities z = and - jxe - if needed. jwe (1) 100 ww v(t) = 25 cos wt V *0.002 F 6.67 5.02 10.2 None of the answers A Moving to another question will save this response. MacBook Pro 20 47 725 F2 F3 F4 #3 & 2$ 48 % 50 67 ALFind: Ib, Ic, Vce, Vb, Vc, Vrb Vre, & Vrc Note: show your solutions no solution means wrong answers. C2 HE 1000μF Rb 560 ΚΩ VCC 12V Rc 2kQ Q1 C1 요 HE 1000μF 2SC1815 R1 2000
- What is the total equivalent (total) inductance Lr of this circuit? 000 30mH L2 R 000 60mH 1 kQ 10 V L3 100mH 000 500mH 43 mH 720 mH O 173 mH o 日 点四RUA 36% DE 40°F PriSc Impr. Écr. F12 F10 F11 F7 F8 F9 F4 F5 F6 * & 3 0 1/4 1/2 4. 5 6. 7 8 2 R Y K L5. Suppose the following circuit is left open for a long time. 5000 22 24 V (a) What is the facial curren What is the carte II What is the ches What is the not the pos 80mF when we close thei 90s after we close the switch? dissipe the resistor 90s arter ene capacitor ons after we close the suit Close the switchi difference across the spacitor 008 after we close the switch across the resisto we close the swit 12 the potential (g) What is the energy stored in the capacitor 90s after we close the switch? (h) What is the energy dissipated by the resistor during the first 90s since the switch is closed?For the circuit below the input voltage is V1(t) flowing through the circuit. + V1 R1 6092 = 12 cos(4t) V. Determine the current C1 HH 10mF L1 300mH
- for the circuit shown below If v_in=5 sin2m10t then corner frequency will be ......Hz 1 UF 2 k Ohm 1 k Ohim 050 060 070 080 vinSaved Messages Shared media A premaccs = Pinned message fr12345@notavaaq.ga - 10 u unl@notavaad 77 videos 10 un SOLD CH A dc voltage E is applied across an RL circuit at t=0. at what time after, is the voltage across the resistor equal to that of the inductor. Photo Saved Me A 0.693TC You: Albur avaaa 0.673TC Channel p proof 0.707TC & LF BU 0.779TC Spotify & TG SC ySpotify E DWAR tli || mov I sebby Photo, vo A SEARCH FOR BUYERS SELLERS AND MAKERS bambeemo ts | 1M GC SH @65: LF BUYER CHE UNIQUE MARKET Photo 316 of 317 ava today at 11:56 AM Upload Docu. Media viewerThe figure shows v(t) and i(t) across a load. Then, the impedance of the load in kQ is: v(t) Volt, i(t) mA -v(t)-it) 250 200 150 100 50 0.dos 0.010 0.015 -50 -100 -150 -200 -250 Time (sec) 1.25Z30° 1.25Z- 45° 1.25Z60° O 1.25Z45°