#9. Find the complex power for the following cases: (a) P = 4 kW, pf = 0.86 (lagging)(b) S = 2 kVA, P = 1.6 kW (capacitive)(c) Vrms = 208⧸20° V, Irms = 6.5⧸−50° A(d) Vrms = 120⧸30° V, Z = 40 + j60 Ω #9. Find the complex power for the following cases:(a) P = 4 kW, pf = 0.86 (lagging)(b) S 2 kVA, P = 1.6 kW (capacitive)208/20° V, Irms = 6.5/-50° A(c) Vrms(d) Vrms120/30° V, Z = 40+ j60 2

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Answered: #9. Find the complex power for the…

#9. Find the complex power for the following cases: (a) P = 4 kW, pf = 0.86 (lagging) (b) S 2 kVA, P = 1.6 kW (capacitive) 208/20° V, Irms = 6.5/-50° A (c) Vrms (d) Vrms 120/30° V, Z = 40+ j60 2

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.2P: Convert the following instantaneous currents to phasors, using cos(t) as the reference. Give your...

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Question

#9. Find the complex power for the following cases: (a) P = 4 kW, pf = 0.86 (lagging) (b) S = 2 kVA, P = 1.6 kW (capacitive) (c) Vrms = 208⧸20° V, Irms = 6.5⧸−50° A (d) Vrms = 120⧸30° V, Z = 40 + j60 Ω

#9. Find the complex power for the following cases:
(a) P = 4 kW, pf = 0.86 (lagging)
(b) S 2 kVA, P = 1.6 kW (capacitive)
208/20° V, Irms = 6.5/-50° A
(c) Vrms
(d) Vrms
120/30° V, Z = 40+ j60 2

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