An electron is traveling through a uniform electric field. The field is constant and given by Part A E = (2.00 x 10-1"N/C) î – (1.20 x 10-11 N/C) §. At t = 0, the electron is at the origin and traveling in the x direction with a speed of 2.80 m/s. What is its position 1.00 s later? V ΑΣφ ? m Submit Request Answer Part B ? y = Submit Request Answer
An electron is traveling through a uniform electric field. The field is constant and given by Part A E = (2.00 x 10-1"N/C) î – (1.20 x 10-11 N/C) §. At t = 0, the electron is at the origin and traveling in the x direction with a speed of 2.80 m/s. What is its position 1.00 s later? V ΑΣφ ? m Submit Request Answer Part B ? y = Submit Request Answer
Chapter6: Gauss's Law
Section: Chapter Questions
Problem 26P: A vector field is pointed along the z-axis, v=ax2+y2z . (a) Find the flux of the vector field...
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Step 1
Given data:
The electric field of intensity is,
At t= 0, electron travelling along x-direction.
The initial speed of an electron is,
v0 = 2.0 m/s
Formula used:
According to Newton's 2nd law,
F= ma
According to Lorentz force equation, the force experienced by the charge q due to electric field is,
F =qE
According to the Kinematical equation of motion,'
the position of an object at time t is,
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