An electron is traveling through a uniform electric field. The field is constant and given by Part A E = (2.00 x 10-1"N/C) î – (1.20 x 10-11 N/C) §. At t = 0, the electron is at the origin and traveling in the x direction with a speed of 2.80 m/s. What is its position 1.00 s later? V ΑΣφ ? m Submit Request Answer Part B ? y = Submit Request Answer

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Chapter6: Gauss's Law
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Problem 26P: A vector field is pointed along the z-axis, v=ax2+y2z . (a) Find the flux of the vector field...
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An electron is traveling through a uniform electric field. The
field is constant and given by
Part A
E = (2.00 x 10-11N/C) î – (1.20 × 10-11 N/C) j.
At t = 0, the electron is at the origin and traveling in the x
direction with a speed of 2.80 m/s.
What is its position 1.00 s later?
ΑΣφ
?
Submit
Request Answer
Part B
ΑΣφ
Y =
Submit
Request Answer
Transcribed Image Text:An electron is traveling through a uniform electric field. The field is constant and given by Part A E = (2.00 x 10-11N/C) î – (1.20 × 10-11 N/C) j. At t = 0, the electron is at the origin and traveling in the x direction with a speed of 2.80 m/s. What is its position 1.00 s later? ΑΣφ ? Submit Request Answer Part B ΑΣφ Y = Submit Request Answer
Expert Solution
Step 1

Given data:

The electric field of intensity is,

E = 2.00×10-11 N/Ci^ -1.20×10-11 N/Cj^ 

At t= 0, electron travelling along x-direction.

The initial speed of an electron is,

v0 = 2.0 m/s

Formula used:

According to Newton's 2nd law,

F= ma

According to Lorentz force equation, the force experienced by the charge q due to electric field is,

F =qE

According to the Kinematical equation of motion,'

the position of an object at time t is,

S = ut  + 12at2

 

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