Data Table 1Enter the calculated molarity and measured conductivity values in the table.Data Table 1: Experimental DataSodiumTotalSodium ChlorideStandard Chloride Volume Concentration (M or Conductivity (µS)(g)(mL)mol/L)Blank100.008.965A0.0059 100.00В0.0531 100.000.1029 100.00

Note: Conductivity values comes from the readings of Conductometer. Molarity can be calculated as:…

Answered: Data Table 1 Enter the calculated…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.10QAP

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The Henry's law constant for the solubility of radon in water at is 9.57106 M/mm Hg. Radon is present with other gases in a sample taken from an aquifer at 30C. Radon has a mole fraction of 2.7106 in the gaseous mixture. The gaseous mixture is shaken with water at a total pressure of 28 atm. Calculate the concentration of radon in the water. Express your answers using the following concentration units. (a) molarity (b) ppm (Assume that the water sample has a density of 1.00 g/mL.)
What is the microscopic explanation for the macroscopic behaviour illustrated in Figure 11.15?
Part III: Determination of Saturated Solutions Molarity (saturated) Tube # Temperature (°C) Molarity (dilute) Absorbance 2 0.6 0.157 20.1 0.291 4 37.6 0.351 50.1 0.500 6. 70.9 0.714 show calculation for Tube #2, Molarity (dilute) (use graph equation): show calculation for Tube #2, Molarity (saturated): 1. Is the relationship between solubility and temperature direct or inverse? Explain.
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Calculate the quantity of lime and soda required for softening one million litre of the following sample of water. If the purities of lime and soda are 80% and 85% respectively. The impurities are Silica mg/lit. CaSO4 = 68 mg/lit. MgCO3 = 884 mg/lit. CaCO3 = 120 mg/lit. 75 mg/lit. MgCl2 = 19 mg/lit. MgSO4 = 30 %3D %3D
Question 3 Which of the following statement/s is/are TRUE? I. The Arrhenius Theory cannot be applied to account for the behavior of the molar conductivity of strong electrolytes, since these solutes are completely dissociated, at least in dilute solutions. II. Debye=Huckel Theory of interionic attraction satisfactorily explains the variation of the molecular conductivity of strong electrolytes with concentration. II. The ions interact with the solvent molecules through dipole-dipole interaction. IV. When an electric potential is applied across the solution, the ions migrate and the ionic atmosphere around these ions is modified. O , I, IV O I, I O , I, II
Question 5 Which of the following statement/s is/are TRUE? I. The Arrhenius Theory cannot be applied to account for the behavior of the molar conductivity of strong electrolytes, since these solutes are completely dissociated, at least in dilute solutions. II. Debye=Huckel Theory of interionic attraction satisfactorily explains the variation of the molecular conductivity of strong electrolytes with concentration. III. The ions interact with the solvent molecules through dipole-dipole interaction. IV. When an electric potential is applied across the solution, the ions migrate and the ionic atmosphere around these ions is modified. O I, II, II O II, II, IV O ,I O I, II O I, II, IV
Based on the following data: Solution Volume of 1.0 M CH3COOH solution Experimental conductivity Corrected conductivity A 4.00 419 414 B 10.00 712 707 Using the data given, calculate the following: 1. Concentration after dilution of each solution using this formula: C1V1=czv2 2. molar conductivity of each solution using this formula: molar conductivity = corrected conductivity/ concentration of solution in molarity 3. Fraction ionized using this formula: fraction ionized = molar conductivity / 3.955x10"5 4. Concentration of all species present in each solution. 5. pH of the solution 6. lonization constant of acetic acid
(b) Calculate the quantity of lime and soda required for softening one million litre of thefollowing sample of water. If the purities of lime and soda are 80% and 85%respectively. The impurities are Silica = 75 mg/lit. MgCl2 = 19 mg/lit. MgSO4 = 30mg/lit. CaSO4 = 68 mg/lit. MgCO3 = 884 mg/lit. CaCO3 = 120 mg/lit.
Ples don`t proved handratting solution
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Data Table 1 Enter the calculated molarity and measured conductivity values in the table. Data Table 1: Experimental Data Sodium Total Sodium Chloride Standard Chloride Volume Concentration (M or Conductivity (uS) (g) (mL) mol/L) Blank 100.00 8.965 A 0.0059 | 100.00