EcoRI recognizes G A-A-T-T-C sequence and cleave/ cut between G and A. How will the DNA fragments look like if EcoRI used for the DNA below? How many fragments are produced? 5- AAAGATTTGAATTTCGAATTCAATTTAAGAATTCCCTTAGAATTTCC-¹3
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- Transcribe and translate the following DNA sequence (nontemplate strand): 5’-ATGGCCGGTTATTAAGCA-3’EcoRI recognizes GA-A-T-T-C sequence and cleave/ cut between G and A. How will the DNA fragments look like if EcoRI is used for the DNA below? How many fragments are produced? -'3 5'-AAAGATTTGAATTTCGAATTCAATTTAAGAATTCCCTTAGAATTTCCThis is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' (i) Draw the structure of hairpin loop that will be formed during the end of transcription. (ii) Describe the function of the hairpin loop during transcription.
- Table I CACGT A GA CTGAGG ACTC CACGTAGACTGAG G ACAC Wild-type beta-globin gene fragment Sickle-cell beta-globin gene fragment > Circle the mutation in DNA of the sickle-cell beta-globin gene fragment Compare fragments of DNA the wild-type and mutant beta-globin genes in the Table I above, what are the similarities and differences you observe?EcoRI --- 5' G - AATTC 3' 5' AGAATTCCGACGTATTAGAATTCTTAT CCGCCGCCGGAATTCT CATCA 3' 3' TCTTAAGGCTGCATAATCTTAAGAATAGGCGGCGGCCTTAAGAGTAGT 5' Number of pieces of DNA , and type of fragment .Numbering the fragments left by cutting the DNA with BAM HI from left to right, which fragment will travel the furthest? BAM HI: GGATCC CCTAGG AATCGGATCCATTTGGACTAAAGGACCCGGATTGGATCCAGGGCCTTTAGTACC TTAGCCTAGGTAAACCTGATTTCCTGGGCCTAACCTAGGTCCCGGAAATCATGG O 3 O 2 4. 1.
- For the chromatogram below, what is the sequence of the template DNA from base 115 to 125? CTGTGTGAAA TTGT TA T C CGC T CACA A T TCCACA CA A CATACGAG CCGGAAG CA T AA 110 120 130 140 150 160 СТТТААСАAТА ТАTTCAATTТС ATAACAATTTC GAAATTGTTATThe chromatogram shows fluorescent peak data from a dye-terminating nucleotide-sequencing reaction. The peaks are shown with shortest fragment on the left to longer fragments on the right. T •C A Select the DNA sequence that matches the data. 5-ТАТAСТТАСGAAGT-3' 5'-GTCCTACGGACGCG–3' 5'-ATATGAATGCTTCA–3' 5'-TGAAGCATTCATAT–3' 5-АСТТCGTAAGTATA-3'Given the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs ( what letter changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - AGGCTCGCCTGT - 5' Mutated DNA Sequence: 3' - AGTCTCGCCTGT - 5'
- This is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: bottom strand is the noncoding strand). 5'-ААCGCATGAGAAAGCCCCCCGGAAGATCACСТТСCGGGGGCТТТАТАТААТТАGC-3' 3'-тTGCGTACтстттCGGGGGGCCTTCTAGTGGAAGGCCCCCGАААТАТАТТААТтCG-5' (i) Draw the structure of hairpin loop that will be formed during transcription. (ii) Illustrate how the hairpin loop structure initiates the termination of transcription.This is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' Draw the structure of hairpin loop that will be formed during the end of transcription.The following DNA sequence was determined by Sanger sequencing, using a 20 nt long sequencing primer that ended ...AGTACAACAA-3'. 5'-agtacaacaa ctctcggtc tacggtacgc ctgcgggcgc gtagccaatc tagcacttcg-3' 3'-tcatgttgtt gagagccag atgccatgcg gacgcccgcg catcggttag atcgtgaagc-5′ A. If the technician forgot to add ddNTPs to the reaction, what would the sequencing chromatogram look like? Blank Many peaks, but only one at each position Overlapping peaks at every position All peaks are black There is only one peak, at 60 nt B.When the reaction is done correctly, ddCTP is labeld with a yellow fluorescent tag. When the Sanger sequencing reaction is complete, what will be the lengths, in nucleotides, of the three shortest products that have the yellow tag? C. Could you perform Illumina sequencing using ddNTPs? Why or why not? Explain.