Answered: Given: Nc = (2.51x1019)(mn/mo)3/2…

Given: Nc = (2.51x1019)(mn/mo)3/2 (T/300)3/2 Nv = (2.51x1019)(mp/mo)3/2 (T/300)3/2 and ni = (NcNv)1/2 e(-Eg/2kT) show that: ni = (2.51x1019) ((mn/mo) * (mp/mo) )3/2 e(-Eg/2kT)

Modern Physics

3rd Edition

ISBN:9781111794378

Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Chapter14: Nuclear Physics Applications

Section: Chapter Questions

Problem 12P

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Concept explainers

Rutherford's scattering experiment

Rutherford’s scattering experiment is also known as the gold foil experiment. This experiment disproved the plum pudding model of J.J. Thomson. In a gold foil experiment, high-energy alpha particles are made to strike a thin gold foil. The scattered alpha particles are detected using a detector. This experiment showed that the positive charge of the atom is at the center. Most of the atom’s mass is also confined to a small volume at the center. This region is known as the nucleus of the atom.

Question

Given:

Nc = (2.51x10¹⁹)(m_n/mo)^3/2 (T/300)^3/2

Nv = (2.51x10¹⁹)(m_p/mo)^3/2 (T/300)^3/2

and ni = (NcNv)^1/2 e^(-Eg/2kT)

show that:

ni = (2.51x10¹⁹) ((m_n/mo) * (m_p/mo) )3/2 e^(-Eg/2kT)

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