Lab Report #4-2-1:0.1 M NH4CI solution, using the given pH data, calculate: [H*], [OH"]:[H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M[H*] = 2.2 x 10-9 M, [OH"]= 4.5 x 10-6 M[H*] = 3.2 x 10-10 M, [OH"]= 3.2 x 10-5 M%3D[H*] = 1.0 x 10-7 M, [OH`]= 1.0 x 10-7 M pH values3.5SolutionsH20 (unboiled)H20 (boiled)7.0NaCl7.0NaC2H3029.1NHẠC14.5NaHCO39.5Na3PO411.9Na2CO311.0

pH of a solution measures acidity of that solution. If pH >7 solution is basic. If pH <7…

Lab Report #4-2-1: 0.1 M NH4CI solution, using the given pH data, calculate: [H*], [OH"]: O [H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M O [H*] = 2.2 x 10-9 M, [OH¯]= 4.5 x 10-6 M O [H*] = 3.2 x 10-10 M, [OH"]= 3.2 x 10-5 M %3D [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M

Lab Report #4-2-1: 0.1 M NH4CI solution, using the given pH data, calculate: [H], [OH"]: O [H] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M O [H] = 2.2 x 10-9 M, [OH¯]= 4.5 x 10-6 M O [H] = 3.2 x 10-10 M, [OH"]= 3.2 x 10-5 M %3D [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter21: Potentiometry

Section: Chapter Questions

Problem 21.14QAP

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Question

Lab Report #4-2-1:
0.1 M NH4CI solution, using the given pH data, calculate: [H*], [OH"]:
[H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M
[H*] = 2.2 x 10-9 M, [OH"]= 4.5 x 10-6 M
[H*] = 3.2 x 10-10 M, [OH"]= 3.2 x 10-5 M
%3D
[H*] = 1.0 x 10-7 M, [OH`]= 1.0 x 10-7 M

pH values
3.5
Solutions
H20 (unboiled)
H20 (boiled)
7.0
NaCl
7.0
NaC2H302
9.1
NHẠC1
4.5
NaHCO3
9.5
Na3PO4
11.9
Na2CO3
11.0

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