Lab Report #6-2-1: 0.1 M Na3PO4 solution, using the given pH data, calculate: [H*], [OH]: [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 m %3D O [H*] = 7.9 x 10-3 M, [OH"]= 1.3 x 10-12 M O [H*] = 1.3 x 10-12 M, [OH]= 7.9 x 10-3 M O [H*] = 2.6 x 10-12 M, [OH]= 3.8 x 103 M

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter21: Potentiometry
Section: Chapter Questions
Problem 21.14QAP
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Question
100%
pH values
3.5
Solutions
H20 (unboiled)
H20 (boiled)
7.0
NaCl
7.0
NaC2H302
9.1
NHẠC1
4.5
NaHCO3
9.5
Na3PO4
11.9
Na2CO3
11.0
Transcribed Image Text:pH values 3.5 Solutions H20 (unboiled) H20 (boiled) 7.0 NaCl 7.0 NaC2H302 9.1 NHẠC1 4.5 NaHCO3 9.5 Na3PO4 11.9 Na2CO3 11.0
Lab Report #6-2-1:
0.1 M Na3PO4 Ssolution, using the given pH data, calculate: [H*], [OH"]:
[H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M
[H*] = 7.9 x 10-3 M, [OH"]= 1.3 x 10-12 M
%D
[H*] = 1.3 x 10-12 M, [OH"]= 7.9 x 10-3 M
[H*] = 2.6 x 10-12 M, [OH"]= 3.8 x 10-3 M
Transcribed Image Text:Lab Report #6-2-1: 0.1 M Na3PO4 Ssolution, using the given pH data, calculate: [H*], [OH"]: [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M [H*] = 7.9 x 10-3 M, [OH"]= 1.3 x 10-12 M %D [H*] = 1.3 x 10-12 M, [OH"]= 7.9 x 10-3 M [H*] = 2.6 x 10-12 M, [OH"]= 3.8 x 10-3 M
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