Let X be a discrete random variable with the following PMF 1 1 for x=-2 8 100 for x = -1 Px(x) = for x = 0 1 for x = 1 for x = 2 4 0 otherwise a) Find E[X] and Var(X) b) Now we define a new random variableY = (x+1)², Find PMF of Y and E[Y]

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.3: Special Probability Density Functions
Problem 30E
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Let X be a discrete random variable with the following PMF
1
1
for x=-2
8
100
for x = -1
Px(x) =
for x = 0
1
for x = 1
for x = 2
4
0
otherwise
a) Find E[X] and Var(X)
b) Now we define a new random variableY = (x+1)², Find PMF of Y and E[Y]
Transcribed Image Text:Let X be a discrete random variable with the following PMF 1 1 for x=-2 8 100 for x = -1 Px(x) = for x = 0 1 for x = 1 for x = 2 4 0 otherwise a) Find E[X] and Var(X) b) Now we define a new random variableY = (x+1)², Find PMF of Y and E[Y]
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