PXV=RXT where v=specificvolume R idealgasconstantfwater-461.5 J/kg.K Therefore V= RXT P 461.5×623 V= 15×106 v=0.01917 m³/kg (b) Usingthgeneralized bmpressibilityhart At P=15MPaandT=350°C, usingompressiblityl thespecificvolumeis, v=0.01246 m³/kg (c) Usingthesteantable At P 15 MPaandT=350°C, usingsteamtable thespecificvolumeis, |v= =0.01148 m³/kg Theerrorinthespecific volumeforthefirsttwocase: Case (a) Theerrorinthespecific volumeis, V-V a C %Error= x100 V C where v=thespecific volume incase (a) v=thespecificvolume incase (c) 0.01917 0.01148 %Error= 0.01148 % Error=67% x100

Refrigeration and Air Conditioning Technology (MindTap Course List)
8th Edition
ISBN:9781305578296
Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Chapter46: Room Air Conditioners
Section: Chapter Questions
Problem 15RQ
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For (b) and (c) upload chart and table images.
PXV=RXT
where v=specificvolume
R= idealgasconstantfwater=461.5 J/kg.K
Therefore
RXT
V=
P
461.5×623
v=
15×106
v=0.01917 m³/kg
(b) Usingthgeneralized bmpressibilityhart
At P=15MPaandT=350°C, usingompressiblityl
thespecificvolumeis,
v=0.01246 m³/kg
(c) Usingthesteamtable
At P=15MPaandT=350°C, using steamtable
thespecificvolumeis,
v=0.01148 m³/kg
Theerrorinthespecificvolumeforthefirsttwocase:
Case (a) Theerrorinthespecific volumeis,
Va-Ve
а
%Error=
×100
where v=thespecific volume incase (a)
v=thespecificvolumeincase (c)
0.01917-0.01148
%Error=
×100
0.01148
% Error=67%
Transcribed Image Text:PXV=RXT where v=specificvolume R= idealgasconstantfwater=461.5 J/kg.K Therefore RXT V= P 461.5×623 v= 15×106 v=0.01917 m³/kg (b) Usingthgeneralized bmpressibilityhart At P=15MPaandT=350°C, usingompressiblityl thespecificvolumeis, v=0.01246 m³/kg (c) Usingthesteamtable At P=15MPaandT=350°C, using steamtable thespecificvolumeis, v=0.01148 m³/kg Theerrorinthespecificvolumeforthefirsttwocase: Case (a) Theerrorinthespecific volumeis, Va-Ve а %Error= ×100 where v=thespecific volume incase (a) v=thespecificvolumeincase (c) 0.01917-0.01148 %Error= ×100 0.01148 % Error=67%
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